如果在错误发生时查看回溯,你会看到类似于:
MemoryError Traceback (most recent call last)
<ipython-input-4-1e538e8d766e> in <module>()
/home/warren/local_scipy/lib/python2.7/site-packages/scipy/interpolate/interpolate.py in __init__(self, x, y, kind, axis, copy, bounds_error, fill_value)
390 else:
391 minval = order + 1
393 self._call = self.__class__._call_spline
394
/home/warren/local_scipy/lib/python2.7/site-packages/scipy/interpolate/interpolate.py in splmake(xk, yk, order, kind, conds)
1754
1755 # the constraint matrix
-> 1756 B = _fitpack._bsplmat(order, xk)
1757 coefs = func(xk, yk, order, conds, B)
1758 return xk, coefs, order
MemoryError:
出现问题的函数是 scipy.interpolate._fitpack._bsplmat(order, xk)
。该函数创建一个形状为 (len(xk), len(xk) + order - 1)
的64位浮点数2D数组,在您的情况下,大小为51GB。
不要使用interp1d
,尝试看看InterpolatedUnivariateSpline
是否适合您的需要。例如:
import numpy as np
from scipy.interpolate import InterpolatedUnivariateSpline
x = np.linspace(0, 10, 80000)
y = np.cos(-x**2/8.0)
f2 = InterpolatedUnivariateSpline(x, y, k=3)
我不会遇到内存错误。
np.cos(-x**2/8.0)
之间的最坏情况误差也小于2e-8。 - Warren Weckesser