忽略您示例图中点之间的平滑插值(这将需要进行一些手动插值,或仅使用更高分辨率的数据),您可以使用 pyplot.fill_between()
:
from matplotlib import pyplot as plt
import numpy as np
x = np.linspace(0, 30, 30)
y = np.sin(x/6*np.pi)
error = np.random.normal(0.1, 0.02, size=y.shape)
y += np.random.normal(0, 0.1, size=y.shape)
plt.plot(x, y, 'k-')
plt.fill_between(x, y-error, y+error)
plt.show()
还可以参考matplotlib示例。
lw
但它似乎不使用与轴相同的单位。 - Benjamin Bannier这基本上是由Evert提供的相同答案,但扩展以展示fill_between
的一些很酷的选项
from matplotlib import pyplot as pl
import numpy as np
pl.clf()
pl.hold(1)
x = np.linspace(0, 30, 100)
y = np.sin(x) * 0.5
pl.plot(x, y, '-k')
x = np.linspace(0, 30, 30)
y = np.sin(x/6*np.pi)
error = np.random.normal(0.1, 0.02, size=y.shape) +.1
y += np.random.normal(0, 0.1, size=y.shape)
pl.plot(x, y, 'k', color='#CC4F1B')
pl.fill_between(x, y-error, y+error,
alpha=0.5, edgecolor='#CC4F1B', facecolor='#FF9848')
y = np.cos(x/6*np.pi)
error = np.random.rand(len(y)) * 0.5
y += np.random.normal(0, 0.1, size=y.shape)
pl.plot(x, y, 'k', color='#1B2ACC')
pl.fill_between(x, y-error, y+error,
alpha=0.2, edgecolor='#1B2ACC', facecolor='#089FFF',
linewidth=4, linestyle='dashdot', antialiased=True)
y = np.cos(x/6*np.pi) + np.sin(x/3*np.pi)
error = np.random.rand(len(y)) * 0.5
y += np.random.normal(0, 0.1, size=y.shape)
pl.plot(x, y, 'k', color='#3F7F4C')
pl.fill_between(x, y-error, y+error,
alpha=1, edgecolor='#3F7F4C', facecolor='#7EFF99',
linewidth=0)
pl.show()