我正在尝试生成一个球体的图形,并在球体表面绘制一些点。(具体来说,这些点是Lebedev积分点) 我希望我的图像看起来与我在网上找到的这个类似:
我首先绘制了一个球面,然后将其与散点图叠加。然而,这导致大多数点被底层球体“吸收”,使它们难以看清。看看这张图:
如何防止我的点被球体遮挡? 这是我用于生成此图的脚本:
import matplotlib.pyplot as plt
from matplotlib import cm, colors
from mpl_toolkits.mplot3d import Axes3D
import numpy as np
# Create a sphere
r = 1
pi = np.pi
cos = np.cos
sin = np.sin
phi, theta = np.mgrid[0.0:pi:100j, 0.0:2.0*pi:100j]
x = r*sin(phi)*cos(theta)
y = r*sin(phi)*sin(theta)
z = r*cos(phi)
#Import data
data = np.genfromtxt('leb.txt')
xx, yy, zz = np.hsplit(data, 3)
#Set colours and render
fig = plt.figure()
ax = fig.add_subplot(111, projection='3d')
ax.plot_surface(
x, y, z, rstride=1, cstride=1, color='c', alpha=0.6, linewidth=0)
ax.scatter(xx,yy,zz,color="k",s=20)
ax.set_xlim([-1,1])
ax.set_ylim([-1,1])
ax.set_zlim([-1,1])
ax.set_aspect("equal")
plt.tight_layout()
#plt.show()
编辑
我已经找到了使用Python的mayavi来实现这个的方法。下面是我的代码:
这是我使用的代码:
from mayavi import mlab
import numpy as np
# Create a sphere
r = 1.0
pi = np.pi
cos = np.cos
sin = np.sin
phi, theta = np.mgrid[0:pi:101j, 0:2 * pi:101j]
x = r*sin(phi)*cos(theta)
y = r*sin(phi)*sin(theta)
z = r*cos(phi)
mlab.figure(1, bgcolor=(1, 1, 1), fgcolor=(0, 0, 0), size=(400, 300))
mlab.clf()
data = np.genfromtxt('leb.txt')
xx, yy, zz = np.hsplit(data, 3)
mlab.mesh(x , y , z, color=(0.0,0.5,0.5))
mlab.points3d(xx, yy, zz, scale_factor=0.05)
mlab.show()