我希望将RGB图像转换为LAB(也称为CIE L* a* b*)颜色空间,并提取L*分量。
以下是我的代码:
from skimage import io, color
from scipy import misc
import matplotlib.pyplot as plt
import cv2
img = misc.imread("/Users/zheyuanlin/Desktop/opencv_tests/parrots.png", mode='RGB')
img_resized = misc.imresize(img, (256, 256), 'bilinear') # resized to 256x256
img_cielab = color.rgb2lab(img_resized, illuminant='D50')
# Rescale due to range of LAB values being L (0-100), a (-128-127), b (-128-127)
cielab_scaled = (img_cielab + [0, 128, 128]) / [100, 255, 255]
cie_l, cie_a, cie_b = cv2.split(cielab_scaled)
""" Display the image """
plt.imshow(cie_l)
plt.show()
这是生成的图像:
![这是plt显示的图像](https://istack.dev59.com/qWX2B.webp)
![在此输入图片描述](https://istack.dev59.com/5319u.webp)