我想使用OpenCV4库创建一个C ++代码,将鱼眼图像转换为全景图像。 我正在使用1400 * 1400像素的鱼眼图像进行测试,并从计算机文件中加载:
构建工作正常,但是当我尝试执行代码时,出现以下错误:
我使用此博客中描述的方法,在全景图像中查找鱼眼图像的对应点: http://www.kscottz.com/dewarped-panoramic-images-from-a-raspberrypi-camera-module/ 该方法可以通过以下方式描述:
我在MacOSX上使用Xcode,并使用终端“ITerm2”来构建和执行我的代码。Segmentation fault: 11
我使用此博客中描述的方法,在全景图像中查找鱼眼图像的对应点: http://www.kscottz.com/dewarped-panoramic-images-from-a-raspberrypi-camera-module/ 该方法可以通过以下方式描述:
.
感谢任何帮助。#include <opencv2/opencv.hpp>
#include <iostream>
#include <vector>
#include <string.h>
using namespace cv;
using namespace std;
const string PATH_IMAGE = "/Users/Kenza/Desktop/Xcode_cpp_opencv/Projection/Projection/Images/img1.jpg";
const double PI = 3.141592653589793;
const int ESC = 27;
int main() {
cout << "********** READ AND DISPLAY THE FISHEYE (=INPUT) IMAGE **********" << endl;
Mat fisheyeImage;
fisheyeImage = imread(PATH_IMAGE, IMREAD_COLOR);
namedWindow("Fisheye Image", WINDOW_AUTOSIZE);
imshow("Fisheye Image", fisheyeImage);
while (waitKey(0) != ESC) {
//wait until the key ESC is pressed
}
destroyWindow("Fisheye Image");
cout << "********** CREATE AND LOAD PARAMETERS FOR THE FISHEYE (=INPUT) AND THE EQUIRECTANGULAR IMAGE (=OUTPOUT) **********" << endl;
int Hf, Wf; //Height and Width of the fisheye image (= input)
double R, Cfx, Cfy; //Radius and Center coordinates for the fisheye image
int He, We; //Height and Width of the equirectangular image (= outpout)
Hf = fisheyeImage.size().height;
Wf = fisheyeImage.size().width;
R = Hf / 2; //The fisheye image is a square of 1400x1400 pixels containing a circle so the radius is half of the width or height size
Cfx = Wf / 2; //The fisheye image is a square so the center in x is located at half the distance of the width
Cfy = Hf / 2; //The fisheye image is a square so the center in y is located at half the distance of the height
He = R;
We = 2 * PI*R;
cout << "********** MAPPING : FINDING THE COORDINATES (Xf,Yf) IN THE FISHEYE IMAGE THAT CORRESPOND TO THE COORDINATE (Xe,Fe) IN THE EQUIRECTANGULAR IMAGE **********" << endl;
Mat mapXf; //Contains all the Xf values of the fisheye image which correspond to each Xe and Ye in the equirectangular image
Mat mapYf; //Contains all the Yf values of the fisheye image which correspond to each Xe and Ye in the equirectangular image
mapXf.zeros(Size(We, He), CV_32FC1); //Initialize mapXf with zeros
mapYf.zeros(Size(We, He), CV_32FC1); //Initialize mapYf with zeros
double r, theta; //Polar coordinates for the fisheye image
double Xf, Yf; //Cartesian coordinates for the fisheye image
for (int Ye = 0; Ye < ((int)He); Ye++) { //For each value of Ye in the equirectangular image...
for (int Xe = 0; Xe < ((int)We); We++) { //For each value of Xe in the equirectangular image..
r = Ye / He * R; //We find the value of r in the fisheye image
theta = Xe / We * 2.0*PI; //We find the value of theta in the fisheye image
Xf = Cfx + r * sin(theta); //We get with r and theta the value of Xf
Yf = Cfy + r * cos(theta); //We get with r and theta the value of Yf
mapXf.at<int>(Ye, Xe) = Xf; //We fill the mapping for Xf
mapYf.at<float>(Ye, Xe) = Yf; //We fill the mapping for Yf
}
}
cout << "********** FISHEYE TO EQUIRECTANGULAR **********" << endl;
Mat equirectangularImage;
equirectangularImage.zeros(Size(We, He), CV_32FC1); //Initialize the equirectangular image with zeros
remap(fisheyeImage, equirectangularImage, mapXf, mapYf, INTER_LINEAR, BORDER_CONSTANT, Scalar(0, 0, 0));
namedWindow("Equirectangular Image", WINDOW_AUTOSIZE);
imshow(" Cartesienne", equirectangularImage);
while (waitKey(0) != ESC) {
//wait until the key ESC is pressed
}
destroyWindow("Equirectangular Image");
return 0;
}