我正在尝试在C语言中实现正向和反向离散余弦变换(DCT)。该代码通过dct()函数将单个输入像素块转换为变换矩阵,然后通过idct()函数将其转换回原始像素值。请参见附加的代码。我的idct输出是连续的244、116、244、116等数值。从idct值的外观来看,我的程序似乎没有起作用。有人能帮我解决问题并给我一个关于每个函数后应该得到什么结果的想法吗?显然,在idct之后,我应该得到非常接近原始输入矩阵的结果。
谢谢
# include <stdio.h>
# define PI 3.14
void dct(float [][]); // Function prototypes
void idct(float [][]); // Function prototypes
void dct(float inMatrix[8][8]){
double dct,
Cu,
sum,
Cv;
int i,
j,
u,
h = 0,
v;
FILE * fp = fopen("mydata.csv", "w");
float dctMatrix[8][8],
greyLevel;
for (u = 0; u < 8; ++u) {
for (v = 0; v < 8; ++v) {
if (u == 0) {
Cu = 1.0 / sqrt(2.0);
} else {
Cu = 1.0;
}
if (v == 0) {
Cv = 1.0 / sqrt(2.0);
} else {
Cu = (1.0);
}
sum = 0.0;
for (i = 0; i < 8; i++) {
for (j = 0; j < 8; j++) {
// Level around 0
greyLevel = inMatrix[i][j];
dct = greyLevel * cos((2 * i + 1) * u * PI / 16.0) *
cos((2 * j + 1) * v * PI / 16.0);
sum += dct;
}
}
dctMatrix[u][v] = 0.25 * Cu * Cv * sum;
fprintf(fp, "\n %f", dctMatrix[u][v]);
}
fprintf(fp, "\n");
}
idct(dctMatrix);
}
void idct(float dctMatrix[8][8]){
double idct,
Cu,
sum,
Cv;
int i,
j,
u,
v;
float idctMatrix[8][8],
greyLevel;
FILE * fp = fopen("mydata.csv", "a");
fprintf(fp, "\n Inverse DCT");
for (i = 0; i < 8; ++i) {
for (j = 0; j < 8; ++j) {
sum = 0.0;
for (u = 0; u < 8; u++) {
for (v = 0; v < 8; v++) {
if (u == 0) {
Cu = 1.0 / sqrt(2.0);
} else {
Cu = 1.0;
}
if (v == 0) {
Cv = 1.0 / sqrt(2.0);
} else {
Cu = (1.0);
}
// Level around 0
greyLevel = dctMatrix[u][v];
idct = (greyLevel * cos((2 * i + 1) * u * PI / 16.0) *
cos((2 * j + 1) * v * PI / 16.0));
sum += idct;
}
}
idctMatrix[i][j] = 0.25 * Cu * Cv * sum;
fprintf(fp, "\n %f", idctMatrix[i][j]);
}
fprintf(fp, "\n");
}
}
int main() {
float
testBlockA[8][8] = { {255, 255, 255, 255, 255, 255, 255, 255},
{255, 255, 255, 255, 255, 255, 255, 255},
{255, 255, 255, 255, 255, 255, 255, 255},
{255, 255, 255, 255, 255, 255, 255, 255},
{255, 255, 255, 255, 255, 255, 255, 255},
{255, 255, 255, 255, 255, 255, 255, 255},
{255, 255, 255, 255, 255, 255, 255, 255},
{255, 255, 255, 255, 255, 255, 255, 255} },
testBlockB[8][8] = {{255, 0, 255, 0, 255, 0, 255, 0},
{0, 255, 0, 255, 0, 255, 0, 255},
{255, 0, 255, 0, 255, 0, 255, 0},
{0, 255, 0, 255, 0, 255, 0, 255},
{255, 0, 255, 0, 255, 0, 255, 0},
{0, 255, 0, 255, 0, 255, 0, 255},
{255, 0, 255, 0, 255, 0, 255, 0},
{0, 255, 0, 255, 0, 255, 0, 255} };
dct(testBlockB);
}
{}
- 这将自动缩进4个空格以获得所需的格式。我最初已经为您完成了此操作,但不知何故,您设法撤消了它。 - Paul R