如何从用户在iOS 6中输入的地址获取纬度和经度

Question

我是iOS新手，正在学习MapKit和CoreLocation技术。我的程序中有两个视图控制器，在第一个视图控制器中有一个文本框，用户可以输入地址，并且有一个按钮。当用户填写完地址后，如果点击按钮，它将跳转到地图视图控制器，其中会有两个注释。一个是用户当前位置的标记，另一个是用户输入的地址的标记。

你能告诉我如何获取用户输入地址的经纬度，并在地图视图上显示该经纬度的注释吗？

先行致谢。

- user1960149

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#import <MapKit/MapKit.h> #import <CoreLocation/CoreLocation.h> - Bhavesh Nayi

Answer 1

这里是代码

#import <MapKit/MapKit.h>
#import <CoreLocation/CoreLocation.h>

+(CLLocationCoordinate2D) getLocationFromAddressString:(NSString*) addressStr {

    double latitude = 0, longitude = 0;
    NSString *esc_addr =  [addressStr stringByAddingPercentEscapesUsingEncoding:NSUTF8StringEncoding];
    NSString *req = [NSString stringWithFormat:@"http://maps.google.com/maps/api/geocode/json?sensor=false&address=%@", esc_addr];
    NSString *result = [NSString stringWithContentsOfURL:[NSURL URLWithString:req] encoding:NSUTF8StringEncoding error:NULL];
    if (result) {
        NSScanner *scanner = [NSScanner scannerWithString:result];
        if ([scanner scanUpToString:@"\"lat\" :" intoString:nil] && [scanner scanString:@"\"lat\" :" intoString:nil]) {
            [scanner scanDouble:&latitude];
            if ([scanner scanUpToString:@"\"lng\" :" intoString:nil] && [scanner scanString:@"\"lng\" :" intoString:nil]) {
                [scanner scanDouble:&longitude];
            }
        }
    }
    CLLocationCoordinate2D center;
    center.latitude = latitude;
    center.longitude = longitude;
    return center;

}

然后调用这个方法。

coordinates = [self getLocationFromAddressString:@"address"];

- chandan

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1. 需要添加安全的https URL
2. 将API密钥放在地址后面

- Gajendra K Chauhan

Answer 2

您可以使用Google地理编码技术实现此功能。只需通过HTTP获取数据并解析即可（它可以返回JSON、KML、XML、CSV格式）。

- (CLLocationCoordinate2D) geoCodeUsingAddress:(NSString *)address
{
    double latitude = 0, longitude = 0;
    NSString *esc_addr =  [address stringByAddingPercentEscapesUsingEncoding:NSUTF8StringEncoding];
    NSString *req = [NSString stringWithFormat:@"http://maps.google.com/maps/api/geocode/json?sensor=false&address=%@", esc_addr];
    NSString *result = [NSString stringWithContentsOfURL:[NSURL URLWithString:req] encoding:NSUTF8StringEncoding error:NULL];
    if (result) {
        NSScanner *scanner = [NSScanner scannerWithString:result];
        if ([scanner scanUpToString:@"\"lat\" :" intoString:nil] && [scanner scanString:@"\"lat\" :" intoString:nil]) {
            [scanner scanDouble:&latitude];
            if ([scanner scanUpToString:@"\"lng\" :" intoString:nil] && [scanner scanString:@"\"lng\" :" intoString:nil]) {
                [scanner scanDouble:&longitude];
            }
        }
    }
    CLLocationCoordinate2D center;
    center.latitude = latitude;
    center.longitude = longitude;
    return center;
}

- Annadurai

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嗨，请问在哪里调用这个函数以及如何调用这个函数？请回复！ - Paresh Hirpara

Answer 3

    #import core location Framework

#import <MapKit/MapKit.h>
#import <CoreLocation/CoreLocation.h>

    //Current Location

    CLLocationManager *locationManager = [[CLLocationManager alloc] init];
        locationManager.delegate = self;
        locationManager.desiredAccuracy = kCLLocationAccuracyBest;
        locationManager.distanceFilter = kCLLocationAccuracyKilometer;
        [locationManager startUpdatingLocation];

        CLLocation *location = [locationManager location];
        coordinate = [location coordinate];
        float latitude = coordinate.latitude;
        float longitude = coordinate.longitude;
        NSLog(@"%f",latitude);
        NSLog(@"%f",longitude);


    and type location you call google webservice and pass type address and
    google api return corrdinate for type address

    http://maps.google.com/maps/api/geocode/json?address=1600+Amphitheatre+Parkway,+Mountain+View,+CA&sensor=false

- Bhavesh Nayi

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从当前位置获取，而不是从用户输入的自定义地址获取。 - Code cracker