如何在使用iPhone SDK 3.x时，从用户输入的完整地址（包括街道、城市等）中获取纬度和经度？
9个回答
30
以下是 unforgiven 代码的更新、更紧凑的版本，使用了最新的 v3 API：
- (CLLocationCoordinate2D) geoCodeUsingAddress:(NSString *)address
{
double latitude = 0, longitude = 0;
NSString *esc_addr = [address stringByAddingPercentEscapesUsingEncoding:NSUTF8StringEncoding];
NSString *req = [NSString stringWithFormat:@"http://maps.google.com/maps/api/geocode/json?sensor=false&address=%@", esc_addr];
NSString *result = [NSString stringWithContentsOfURL:[NSURL URLWithString:req] encoding:NSUTF8StringEncoding error:NULL];
if (result) {
NSScanner *scanner = [NSScanner scannerWithString:result];
if ([scanner scanUpToString:@"\"lat\" :" intoString:nil] && [scanner scanString:@"\"lat\" :" intoString:nil]) {
[scanner scanDouble:&latitude];
if ([scanner scanUpToString:@"\"lng\" :" intoString:nil] && [scanner scanString:@"\"lng\" :" intoString:nil]) {
[scanner scanDouble:&longitude];
}
}
}
CLLocationCoordinate2D center;
center.latitude = latitude;
center.longitude = longitude;
return center;
}
该代码假设“location”的坐标先出现，例如在“viewport”坐标之前，因为它只取出“lng”和“lat”键下找到的第一个坐标。如果您担心这里使用的简单扫描技术，请随意使用适当的JSON扫描器（例如SBJSON）。
- Thomas Tempelmann
4
4这种方法效果很好。我发现一个漏洞，可能是因为Google改变了响应格式。scanUpToString和scanString在":"前应该再加一个空格。应该像这样：scanUpToString:@""lat" :"和scanString:@""lat" :"（用于lat和lng两者）。 - cberkley
@cberkley 我已经做出了更改，但为了安全起见，扫描程序应该被更改为不在意纬度/经度和冒号之间的空格。我们永远不知道谷歌何时会再次“修复”这个糟糕的格式。事实上，'russes'版本可能更适合这种情况。 - Thomas Tempelmann
1我发布了我的解决方案，因为在2011年字符串扫描器似乎无法工作。让SBJson解析Google的响应对于从斯坦福CS193在线课程学习iOS编码的初学者来说是有意义的。 - russes
如果您在地址参数中输入“test”会怎样？ - Gajendra K Chauhan
7
这里有一个从谷歌获取纬度和经度的类似解决方案。注意：此示例使用SBJson库，您可以在github上找到：
+ (CLLocationCoordinate2D) geoCodeUsingAddress: (NSString *) address
{
CLLocationCoordinate2D myLocation;
// -- modified from the stackoverflow page - we use the SBJson parser instead of the string scanner --
NSString *esc_addr = [address stringByAddingPercentEscapesUsingEncoding: NSUTF8StringEncoding];
NSString *req = [NSString stringWithFormat: @"http://maps.google.com/maps/api/geocode/json?sensor=false&address=%@", esc_addr];
NSDictionary *googleResponse = [[NSString stringWithContentsOfURL: [NSURL URLWithString: req] encoding: NSUTF8StringEncoding error: NULL] JSONValue];
NSDictionary *resultsDict = [googleResponse valueForKey: @"results"]; // get the results dictionary
NSDictionary *geometryDict = [ resultsDict valueForKey: @"geometry"]; // geometry dictionary within the results dictionary
NSDictionary *locationDict = [ geometryDict valueForKey: @"location"]; // location dictionary within the geometry dictionary
// -- you should be able to strip the latitude & longitude from google's location information (while understanding what the json parser returns) --
DLog (@"-- returning latitude & longitude from google --");
NSArray *latArray = [locationDict valueForKey: @"lat"]; NSString *latString = [latArray lastObject]; // (one element) array entries provided by the json parser
NSArray *lngArray = [locationDict valueForKey: @"lng"]; NSString *lngString = [lngArray lastObject]; // (one element) array entries provided by the json parser
myLocation.latitude = [latString doubleValue]; // the json parser uses NSArrays which don't support "doubleValue"
myLocation.longitude = [lngString doubleValue];
return myLocation;
}
- russes
4
更新版本，使用iOS JSON：
- (CLLocationCoordinate2D)getLocation:(NSString *)address {
CLLocationCoordinate2D center;
NSString *esc_addr = [address stringByAddingPercentEscapesUsingEncoding:NSUTF8StringEncoding];
NSString *req = [NSString stringWithFormat:@"http://maps.google.com/maps/api/geocode/json?sensor=false&address=%@", esc_addr];
NSData *responseData = [[NSData alloc] initWithContentsOfURL:
[NSURL URLWithString:req]]; NSError *error;
NSMutableDictionary *responseDictionary = [NSJSONSerialization
JSONObjectWithData:responseData
options:nil
error:&error];
if( error )
{
NSLog(@"%@", [error localizedDescription]);
center.latitude = 0;
center.longitude = 0;
return center;
}
else {
NSArray *results = (NSArray *) responseDictionary[@"results"];
NSDictionary *firstItem = (NSDictionary *) [results objectAtIndex:0];
NSDictionary *geometry = (NSDictionary *) [firstItem objectForKey:@"geometry"];
NSDictionary *location = (NSDictionary *) [geometry objectForKey:@"location"];
NSNumber *lat = (NSNumber *) [location objectForKey:@"lat"];
NSNumber *lng = (NSNumber *) [location objectForKey:@"lng"];
center.latitude = [lat doubleValue];
center.longitude = [lng doubleValue];
return center;
}
}
- mrd
3
以下方法所做的就是您要求的。您需要插入您的Google地图密钥，以便它可以正确运行。
- (CLLocationCoordinate2D) geoCodeUsingAddress:(NSString *)address{
int code = -1;
int accuracy = -1;
float latitude = 0.0f;
float longitude = 0.0f;
CLLocationCoordinate2D center;
// setup maps api key
NSString * MAPS_API_KEY = @"YOUR GOOGLE MAPS KEY HERE";
NSString *escaped_address = [address stringByAddingPercentEscapesUsingEncoding: NSUTF8StringEncoding];
// Contact Google and make a geocoding request
NSString *requestString = [NSString stringWithFormat:@"http://maps.google.com/maps/geo?q=%@&output=csv&oe=utf8&key=%@&sensor=false&gl=it", escaped_address, MAPS_API_KEY];
NSURL *url = [NSURL URLWithString:requestString];
NSString *result = [NSString stringWithContentsOfURL: url encoding: NSUTF8StringEncoding error:NULL];
if(result){
// we got a result from the server, now parse it
NSScanner *scanner = [NSScanner scannerWithString:result];
[scanner scanInt:&code];
if(code == 200){
// everything went off smoothly
[scanner scanString:@"," intoString:nil];
[scanner scanInt:&accuracy];
//NSLog(@"Accuracy: %d", accuracy);
[scanner scanString:@"," intoString:nil];
[scanner scanFloat:&latitude];
[scanner scanString:@"," intoString:nil];
[scanner scanFloat:&longitude];
center.latitude = latitude;
center.longitude = longitude;
return center;
}
else{
// the server answer was not the one we expected
UIAlertView *alert = [[[UIAlertView alloc]
initWithTitle: @"Warning"
message:@"Connection to Google Maps failed"
delegate:nil
cancelButtonTitle:nil
otherButtonTitles:@"OK", nil] autorelease];
[alert show];
center.latitude = 0.0f;
center.longitude = 0.0f;
return center;
}
}
else{
// no result back from the server
UIAlertView *alert = [[[UIAlertView alloc]
initWithTitle: @"Warning"
message:@"Connection to Google Maps failed"
delegate:nil
cancelButtonTitle:nil
otherButtonTitles:@"OK", nil] autorelease];
[alert show];
center.latitude = 0.0f;
center.longitude = 0.0f;
return center;
}
}
center.latitude = 0.0f;
center.longitude = 0.0f;
return center;
}
- Massimo Cafaro
1
这段代码现在不起作用，因为我的实时应用程序无法正常工作...!?! - Manish Jain
1
还有CoreGeoLocation，它将功能封装在框架（Mac）或静态库（iPhone）中。如果您对Google或Yahoo有偏好，它支持通过这两个服务进行查找。
- Jablair
1
对于谷歌地图密钥解决方案，如上所述的不可原谅，难道不必使应用程序免费吗？根据谷歌的条款和条件：9.1 免费，公共访问您的地图 API 实现。您的地图 API 实现必须对用户普遍免费开放。
使用 SDK 中的地图工具包 3.0，可以轻松完成此操作。请参阅苹果的手册或按照以下步骤：https://developer.apple.com/documentation/mapkit
使用 SDK 中的地图工具包 3.0，可以轻松完成此操作。请参阅苹果的手册或按照以下步骤：https://developer.apple.com/documentation/mapkit
- gammapoint
0
func geoCodeUsingAddress(address: NSString) -> CLLocationCoordinate2D {
var latitude: Double = 0
var longitude: Double = 0
let addressstr : NSString = "http://maps.google.com/maps/api/geocode/json?sensor=false&address=\(address)" as NSString
let urlStr = addressstr.addingPercentEncoding(withAllowedCharacters: .urlQueryAllowed)
let searchURL: NSURL = NSURL(string: urlStr! as String)!
do {
let newdata = try Data(contentsOf: searchURL as URL)
if let responseDictionary = try JSONSerialization.jsonObject(with: newdata, options: []) as? NSDictionary {
print(responseDictionary)
let array = responseDictionary.object(forKey: "results") as! NSArray
let dic = array[0] as! NSDictionary
let locationDic = (dic.object(forKey: "geometry") as! NSDictionary).object(forKey: "location") as! NSDictionary
latitude = locationDic.object(forKey: "lat") as! Double
longitude = locationDic.object(forKey: "lng") as! Double
}} catch {
}
var center = CLLocationCoordinate2D()
center.latitude = latitude
center.longitude = longitude
return center
}
- Piyush Sinroja
1
answer in latest swift 3.0 - Piyush Sinroja
0
- (void)viewDidLoad
{
app=(AppDelegate *)[[UIApplication sharedApplication] delegate];
NSLog(@"%@", app.str_address);
NSLog(@"internet connect");
NSString *Str_address=_txt_zipcode.text;
double latitude1 = 0, longitude1 = 0;
NSString *esc_addr = [ Str_address stringByAddingPercentEscapesUsingEncoding:NSUTF8StringEncoding];
NSString *req = [NSString stringWithFormat:@"http://maps.google.com/maps/api/geocode/json?sensor=false&address=%@", esc_addr];
NSString *result = [NSString stringWithContentsOfURL:[NSURL URLWithString:req] encoding:NSUTF8StringEncoding error:NULL];
if (result)
{
NSScanner *scanner = [NSScanner scannerWithString:result];
if ([scanner scanUpToString:@"\"lat\" :" intoString:nil] && [scanner scanString:@"\"lat\" :" intoString:nil])
{
[scanner scanDouble:&latitude1];
if ([scanner scanUpToString:@"\"lng\" :" intoString:nil] && [scanner scanString:@"\"lng\" :" intoString:nil])
{
[scanner scanDouble:&longitude1];
}
}
}
//in #.hfile
// CLLocationCoordinate2D lat;
// CLLocationCoordinate2D lon;
// float address_latitude;
// float address_longitude;
lat.latitude=latitude1;
lon.longitude=longitude1;
address_latitude=lat.latitude;
address_longitude=lon.longitude;
}
- Paresh Hirpara
网页内容由stack overflow 提供, 点击上面的可以查看英文原文，
原文链接
原文链接