将一个列表的列表馈送给pd.DataFrame
是一种更高效的方法:
s = pd.Series([np.array([53.5688348969, 31.2542494769, 18.002043765]),
np.array([46.845084292, 27.0833015735, 15.5997887379]),
np.array([52.8701581666, 30.7347431703, 17.6379377917]),
np.array([47.9535624339, 27.7063099999, 15.9126963643]),
np.array([51.2900606534, 29.600945626, 16.8756260105])],
index=['03-Sep-15', '04-Sep-15', '08-Sep-15', '09-Sep-15', '10-Sep-15'])
df = pd.DataFrame(s.values.tolist(), index=s.index)
print(df)
0 1 2
03-Sep-15 53.568835 31.254249 18.002044
04-Sep-15 46.845084 27.083302 15.599789
08-Sep-15 52.870158 30.734743 17.637938
09-Sep-15 47.953562 27.706310 15.912696
10-Sep-15 51.290061 29.600946 16.875626
基准测试Python 3.6 / Pandas 0.19:
%timeit pd.DataFrame(s.values.tolist(), index=s.index)
%timeit s.apply(pd.Series)