使用
combn
来获取一列中所有名称的组合(在以下示例中,我假设您仅想要两列的组合),并使用
Map
循环运行。
使用R中的mtcars数据进行示例:
colc<-names(mtcars)
colcc<-combn(colc,2)
colcc<-data.frame(colcc)
kk<-Map(function(x)lm(as.formula(paste(colcc[1,x],"~",paste(colcc[2,x],collapse="+"))),data=mtcars), as.list(1:nrow(colcc)))
head(kk)
[[1]]
Call:
lm(formula = as.formula(paste(colcc[1, x], "~", paste(colcc[2,
x], collapse = "+"))), data = mtcars)
Coefficients:
(Intercept) cyl
37.885 -2.876
[[2]]
Call:
lm(formula = as.formula(paste(colcc[1, x], "~", paste(colcc[2,
x], collapse = "+"))), data = mtcars)
Coefficients:
(Intercept) disp
29.59985 -0.04122
[[3]]
Call:
lm(formula = as.formula(paste(colcc[1, x], "~", paste(colcc[2,
x], collapse = "+"))), data = mtcars)
Coefficients:
(Intercept) hp
30.09886 -0.06823
[[4]]
Call:
lm(formula = as.formula(paste(colcc[1, x], "~", paste(colcc[2,
x], collapse = "+"))), data = mtcars)
Coefficients:
(Intercept) drat
-7.525 7.678
[[5]]
Call:
lm(formula = as.formula(paste(colcc[1, x], "~", paste(colcc[2,
x], collapse = "+"))), data = mtcars)
Coefficients:
(Intercept) wt
37.285 -5.344
[[6]]
Call:
lm(formula = as.formula(paste(colcc[1, x], "~", paste(colcc[2,
x], collapse = "+"))), data = mtcars)
Coefficients:
(Intercept) qsec
-5.114 1.412
combn
和apply
函数来解决您的问题。 - MetricsGGally
еҢ…дёӯзҡ„ggpairs
еҮҪж•°пјҡhttp://www.r-bloggers.com/example-9-17-much-better-pairs-plots/ - Ben Bolkerpairapply
函数存在于某个地方 - 尽管我找不到...虽然下面的combn
解决方案基本上可以实现。 - Ben Bolker