我正在尝试获取Android上OpenGL 2.0的最大纹理大小限制。但我发现以下指令仅在当前处于OpenGL上下文中时才起作用,换句话说,我必须拥有一个GL Surface和一个GL Renderer等内容,而这并不是我想要的。
int[] maxTextureSize = new int[1];
GLES20.glGetIntegerv(GLES20.GL_MAX_TEXTURE_SIZE, maxTextureSize, 0);
因此,我提出了下一个算法,它可以在不创建任何表面或渲染器的情况下为我提供最大的纹理尺寸。 它能够正确工作,所以我的问题是这是否适用于所有Android设备,并且如果有人发现任何错误,请告诉我。
public int getMaximumTextureSize()
{
EGL10 egl = (EGL10)EGLContext.getEGL();
EGLDisplay display = egl.eglGetDisplay(EGL10.EGL_DEFAULT_DISPLAY);
// Initialise
int[] version = new int[2];
egl.eglInitialize(display, version);
// Query total number of configurations
int[] totalConfigurations = new int[1];
egl.eglGetConfigs(display, null, 0, totalConfigurations);
// Query actual list configurations
EGLConfig[] configurationsList = new EGLConfig[totalConfigurations[0]];
egl.eglGetConfigs(display, configurationsList, totalConfigurations[0], totalConfigurations);
int[] textureSize = new int[1];
int maximumTextureSize = 0;
// Iterate through all the configurations to located the maximum texture size
for (int i = 0; i < totalConfigurations[0]; i++)
{
// Only need to check for width since opengl textures are always squared
egl.eglGetConfigAttrib(display, configurationsList[i], EGL10.EGL_MAX_PBUFFER_WIDTH, textureSize);
// Keep track of the maximum texture size
if (maximumTextureSize < textureSize[0])
{
maximumTextureSize = textureSize[0];
}
Log.i("GLHelper", Integer.toString(textureSize[0]));
}
// Release
egl.eglTerminate(display);
Log.i("GLHelper", "Maximum GL texture size: " + Integer.toString(maximumTextureSize));
return maximumTextureSize;
}