为了进一步解释@wii上面的评论,您正在寻找np.ndenumerate
。
通常,您会避免显式创建列表,而是使用迭代器。例如:
for (i,j,k), val in np.ndenumerate(your_3d_array):
assert val == your_3d_array[i,j,k]
for ind, val in np.ndenumerate(your_3d_array):
assert val == your_3d_array[ind]
然而,如果你确实想要创建完整的中间列表,你可以使用:
list(np.ndenumerate(your_3d_array))
作为一个更完整的例子:
In [1]: import numpy as np
In [2]: x = np.arange(3*4*5).reshape(3, 4, 5)
In [3]: x
Out[7]:
array([[[ 0, 1, 2, 3, 4],
[ 5, 6, 7, 8, 9],
[10, 11, 12, 13, 14],
[15, 16, 17, 18, 19]],
[[20, 21, 22, 23, 24],
[25, 26, 27, 28, 29],
[30, 31, 32, 33, 34],
[35, 36, 37, 38, 39]],
[[40, 41, 42, 43, 44],
[45, 46, 47, 48, 49],
[50, 51, 52, 53, 54],
[55, 56, 57, 58, 59]]])
In [4]: list(np.ndenumerate(x))
Out [4]:
[((0, 0, 0), 0),
((0, 0, 1), 1),
((0, 0, 2), 2),
((0, 0, 3), 3),
...
((2, 3, 1), 56),
((2, 3, 2), 57),
((2, 3, 3), 58),
((2, 3, 4), 59)]
numpy.ndenumerate
。 - wwii