我认为你可以使用mask
并将参数skipna=True
添加到mean
中,而不是使用dropna
。如果需要替换0
值,则还需要更改条件为data.artist_hotness == 0
,如果需要替换NaN
值,则需要使用data.artist_hotness.isnull()
:
import pandas as pd
import numpy as np
data = pd.DataFrame({'artist_hotness': [0,1,5,np.nan]})
print (data)
artist_hotness
0 0.0
1 1.0
2 5.0
3 NaN
mean_artist_hotness = data['artist_hotness'].mean(skipna=True)
print (mean_artist_hotness)
2.0
data['artist_hotness']=data.artist_hotness.mask(data.artist_hotness == 0,mean_artist_hotness)
print (data)
artist_hotness
0 2.0
1 1.0
2 5.0
3 NaN
或者使用{{link1:loc
}},但省略列名:
data.loc[data.artist_hotness == 0, 'artist_hotness'] = mean_artist_hotness
print (data)
artist_hotness
0 2.0
1 1.0
2 5.0
3 NaN
data.artist_hotness.loc[data.artist_hotness == 0, 'artist_hotness'] = mean_artist_hotness
print (data)
索引错误:(0 True 1 False 2 False 3 False,'artist_hotness')。
另一个解决方案是使用指定列的
DataFrame.replace
。
data=data.replace({'artist_hotness': {0: mean_artist_hotness}})
print (data)
aa artist_hotness
0 0.0 2.0
1 1.0 1.0
2 5.0 5.0
3 NaN NaN
或者如果需要替换所有列中的0
值:
import pandas as pd
import numpy as np
data = pd.DataFrame({'artist_hotness': [0,1,5,np.nan], 'aa': [0,1,5,np.nan]})
print (data)
aa artist_hotness
0 0.0 0.0
1 1.0 1.0
2 5.0 5.0
3 NaN NaN
mean_artist_hotness = data['artist_hotness'].mean(skipna=True)
print (mean_artist_hotness)
2.0
data=data.replace(0,mean_artist_hotness)
print (data)
aa artist_hotness
0 2.0 2.0
1 1.0 1.0
2 5.0 5.0
3 NaN NaN
如果需要将所有列中的
NaN
替换,使用
DataFrame.fillna
:
data=data.fillna(mean_artist_hotness)
print (data)
aa artist_hotness
0 0.0 0.0
1 1.0 1.0
2 5.0 5.0
3 2.0 2.0
但如果仅在一些列中使用Series.fillna
:
data['artist_hotness'] = data.artist_hotness.fillna(mean_artist_hotness)
print (data)
aa artist_hotness
0 0.0 0.0
1 1.0 1.0
2 5.0 5.0
3 NaN 2.0