我正在使用Python中的libsvm(svmutils)进行分类任务。分类器是精确的。然而,我得到的输出如下:
有没有办法可以禁止出现这个对话框?分类器完全正常,只是我好奇。此外,“准确度”代表什么?为什么在我的情况下为0%?(数据在80个维度中不重叠。总共4个类别。我也已经适当地进行了归一化。)
*
optimization finished, #iter = 75
nu = 0.000021
obj = -0.024330, rho = 0.563710
nSV = 26, nBSV = 0
Total nSV = 26
*
optimization finished, #iter = 66
nu = 0.000030
obj = -0.035536, rho = -0.500676
nSV = 21, nBSV = 0
Total nSV = 21
*
optimization finished, #iter = 78
nu = 0.000029
obj = -0.033921, rho = -0.543311
nSV = 23, nBSV = 0
Total nSV = 23
*
optimization finished, #iter = 90
nu = 0.000030
obj = -0.035333, rho = -0.634721
nSV = 23, nBSV = 0
Total nSV = 23
Accuracy = 0% (0/1) (classification)
Accuracy = 0% (0/1) (classification)
Accuracy = 0% (0/1) (classification)
Accuracy = 0% (0/1) (classification)
有没有办法可以禁止出现这个对话框?分类器完全正常,只是我好奇。此外,“准确度”代表什么?为什么在我的情况下为0%?(数据在80个维度中不重叠。总共4个类别。我也已经适当地进行了归一化。)