在xyplot()中更改背景颜色

Question

我试图改变条纹的背景颜色（它是一个6×6的矩阵，我已经将6种条纹颜色存储在名为cola的向量中）。我尝试结合网上找到的东西，但结果完全不对：现在我只得到了所有垂直条纹都是黄色的，而水平条纹都是红色的:(

library(lattice)
library(latticeExtra)
B<-structure(list(ylab = c(0, 0, -1, -1, -1, -1, 0, 0, -1, -1, -1, 
-1, 1, 1, 0, 0, 0, -1, 1, 1, 0, 0, 1, -1, 1, 1, 0, -1, 0, -1, 
1, 1, 1, 1, 1, 0), xlab = c(0, -1.02679909743483, -4.31389840050087, 
-4.72016163070677, -3.82773068058066, -4.95060796675797, 1.02679909743483, 
0, -3.28709930306604, -3.69336253327194, -2.80093158314584, -3.92380886932314, 
4.31389840050087, 3.28709930306604, 0, -0.406263230205904, 0.486167719920203, 
-0.636709566257106, 4.72016163070677, 3.69336253327194, 0.406263230205904, 
0, 0.892430950126108, -0.230446336051202, 3.82773068058066, 2.80093158314584, 
-0.486167719920203, -0.892430950126108, 0, -1.12287728617731, 
4.95060796675797, 3.92380886932314, 0.636709566257106, 0.230446336051202, 
1.12287728617731, 0), zlab = c(1, 0.435981356312883, 1.28746578953454e-08, 
1.64728897189548e-09, 9.04719004157784e-08, 1.22124532708767e-15, 
0.435981356312883, 1, 2.30452944283144e-07, 1.23923277972615e-07, 
1.38063360011209e-06, 7.7715611723761e-16, 1.28746578953454e-08, 
2.30452944283144e-07, 1, 0.654543666603895, 0.608788895482761, 
3.33066907387547e-16, 1.64728897189548e-09, 1.23923277972615e-07, 
0.654543666603895, 1, 0.0429030453016164, 0, 9.04719004157784e-08, 
1.38063360011209e-06, 0.608788895482761, 0.0429030453016164, 
1, 4.22994972382185e-14, 1.22124532708767e-15, 7.7715611723761e-16, 
3.33066907387547e-16, 0, 4.22994972382185e-14, 1), g1 = structure(c(1L, 
2L, 3L, 4L, 5L, 6L, 1L, 2L, 3L, 4L, 5L, 6L, 1L, 2L, 3L, 4L, 5L, 
6L, 1L, 2L, 3L, 4L, 5L, 6L, 1L, 2L, 3L, 4L, 5L, 6L, 1L, 2L, 3L, 
4L, 5L, 6L), .Label = c("1", "2", "5", "6", "7", "8"), class = "factor"), 
    g2 = structure(c(1L, 1L, 1L, 1L, 1L, 1L, 2L, 2L, 2L, 2L, 
    2L, 2L, 3L, 3L, 3L, 3L, 3L, 3L, 4L, 4L, 4L, 4L, 4L, 4L, 5L, 
    5L, 5L, 5L, 5L, 5L, 6L, 6L, 6L, 6L, 6L, 6L), .Label = c("1", 
    "2", "5", "6", "7", "8"), class = "factor")), .Names = c("ylab", 
"xlab", "zlab", "g1", "g2"), row.names = c(NA, -36L), class = "data.frame")
mycol<-c("light grey", "light grey", "purple", "purple", "purple", "purple", 
"light grey", "light grey", "purple", "purple", "purple", "purple", 
"light green", "light green", "light grey", "light grey", "light grey", 
"purple", "light green", "light green", "light grey", "light grey", 
"light green", "purple", "light green", "light green", "light grey", 
"purple", "light grey", "purple", "light green", "light green", 
"light green", "light green", "light green", "light grey")

mycola <- rainbow(6)


useOuterStrips(bwplot(~B$ylab|B$g1*B$g2,ylab="",xlab="",as.table=TRUE, par.settings=list(strip.background=list(col=mycola)),panel=function(...,bg){
    panel.fill(col=mycol[panel.number()])
},strip = function(..., bg) {
     strip.fill=col[which.packet()]
   },scale=list(draw=FALSE)))

- user189035

---

如果我理解正确，您想将水平和垂直条的每个元素分配不同的颜色？目前，您可以设置所有水平条的颜色，但不能单独设置。 - Seth

是的，这就是我想做的。那么你知道我怎样才能完全移除这些条纹吗？我会尝试着给矩阵的外部行/列上色或调整大小。 - user189035

+1 感谢您提出这个有趣的问题，特别是提供可重现的示例。 - Josh O'Brien

Answer 1

这段代码（快速改编自我对此Stack Overflow问题的回答）可以帮助您解决部分问题。（如果能够将其适应于在每个条带中打印文本，我会很感兴趣了解如何实现）。

需要注意的一点是，自定义条带函数需要直接传递给useOuterStrips()，而不是嵌套调用bwplot()。

# Create a function to be passes to "strip=" argument of xyplot
myStripStyle <- function(which.panel, factor.levels, ...) {
    panel.rect(0, 0, 1, 1,
               col = bgColors[which.panel],
               border = 1)
    ## This call to panel.text() commented out because it does not
    ## work as I would have expected/hoped it to
    # panel.text(x = 0.5, y = 0.5,
    #            font=2,
    #            lab = factor.levels[which.panel],
    #            col = "black")
}

mycola <- rainbow(6)
bgColors <- mycola

useOuterStrips(bwplot(~B$ylab|B$g1*B$g2,ylab="",xlab="",as.table=TRUE,
                      panel=function(...,bg){
                          panel.fill(col=mycol[panel.number()])
                      },
                      scale=list(draw=FALSE)),
               strip = myStripStyle,
               strip.left = myStripStyle)

- Josh O'Brien