使用OpenCV中的HoughLines函数,能否确定与图像底部相对的结果线的角度?
如果您使用HoughLines函数,它将为您提供已由两个参数定义的线:theta和rho,如下所示
vector<Vec2f> lines;
// detect lines
HoughLines(image, lines, 1, CV_PI/180, 150, 0, 0 );
// get lines
for( size_t i = 0; i < lines.size(); i++ )
{
float rho = lines[i][0], theta = lines[i][1];
....
}
如果您使用HoughLinesP函数,您将获得由两个点定义的直线,您只需要根据图像计算两点之间的直线角度,例如:
vector<Vec4i> lines;
// detect the lines
HoughLinesP(image, lines, 1, CV_PI/180, 50, 50, 10 );
for( size_t i = 0; i < lines.size(); i++ )
{
Vec4i l = lines[i];
// draw the lines
Point p1, p2;
p1=Point(l[0], l[1]);
p2=Point(l[2], l[3]);
//calculate angle in radian, if you need it in degrees just do angle * 180 / PI
float angle = atan2(p1.y - p2.y, p1.x - p2.x);
.......
}