我有一个分形图像创建器。它创建一个类似随机分形树的东西。完成后,它会提示用户保存这个树。目前,我已经将其保存为.svg格式,并且可以工作。但是我想它以更方便的文件类型保存,比如jpeg。有什么想法吗? 代码:
import turtle
import random
from sys import exit
from time import clock
import canvasvg
turtle.colormode(255)
red = 125
green = 70
blue = 38
pen = 10
def saveImg():
print("Done.")
save = input("Would you like to save this tree? Y/N \n")
if save.upper() == "Y":
t.hideturtle()
name = input("What would you like to name it? \n")
nameSav = name + ".svg"
ts = turtle.getscreen().getcanvas()
canvasvg.saveall(nameSav, ts)
elif save.upper() == "N":
def runChk():
runAgain = input("Would you like to run again? Y/N (N will exit)")
if runAgain.upper() == "Y":
print("Running")
main()
elif runAgain.upper() == "N":
print("Exiting...")
exit()
else:
print("Invalid response.")
runChk()
runChk()
else:
print("Invalid response.")
saveImg()
def tree(branchLen, t, red, green, blue, pen):
time = str(round(clock()))
print("Drawing... " + time)
if branchLen > 3:
pen = pen*0.8
t.pensize(pen)
if (red > 10 and green < 140):
red = red - 15
green = green + 8
if branchLen > 5:
angle = random.randrange(18, 55)
angleTwo = 0.5*angle
sub = random.randrange(1,16)
t.color(red, green, blue)
t.forward(branchLen)
t.right(angleTwo)
tree(branchLen-sub,t, red, green, blue, pen)
t.left(angle)
tree(branchLen-sub, t, red, green, blue, pen)
t.right(angleTwo)
t.backward(branchLen)
def main():
t = turtle.Turtle()
myWin = turtle.Screen()
t.speed(0)
t.hideturtle()
t.left(90)
t.up()
t.backward(100)
t.down()
print("Please wait while I draw...")
tree(random.randrange(60,95),t,red,green,blue, pen)
saveImg()
main()
tmp.svg
是指nameSav
吗?还是tmp.svg
是由 os.path 创建的文件? - Lillzos.chdir()
更改目录,将目录路径包含在open()
中(例如open(os.path.join(savedir, nameSav), 'wb')
),或要求用户输入包含路径的文件名。 - mhawke