如何使用networkx和matplotlib绘制权重标签？

Question

我正在学习图形，所以我想使用Python中的networkx和matplotlib绘制给定字典的图形，这是我的代码：

import networkx as nx
import matplotlib.pyplot as plt
G = nx.Graph()
graph = {
    "A":["B","C"],
    "B":["D","E"],
    "C":["E","F"],
    "D":["B","G"],
    "E":["B","C"],
    "F":["C","G"],
    "G":["D","F"]
}
x=10
for vertex, edges in graph.items():
    G.add_node("%s" % vertex)
    x+=2
    for edge in edges:
        G.add_node("%s" % edge)
        G.add_edge("%s" % vertex, "%s" % edge, weight = x)
        print("'%s' it connects with '%s'" % (vertex,edge))
nx.draw(G,with_labels=True)

plt.show()

我已经尝试使用函数draw_networkx_edge_labels，但似乎需要一个位置，而我没有这个位置，因为我是动态添加节点的，所以我需要一种方法来绘制边缘标签，以适应我的当前实现。

- Alexis

Answer 1

添加所有节点后，绘制图形以便计算位置并根据其使用 nx.draw_networkx_edge_labels(...) 进行标签绘制：

import networkx as nx
import matplotlib.pyplot as plt
G = nx.Graph()
graph = {
    "A":["B","C"],
    "B":["D","E"],
    "C":["E","F"],
    "D":["B","G"],
    "E":["B","C"],
    "F":["C","G"],
    "G":["D","F"]
}
x=10
for vertex, edges in graph.items():
    G.add_node("%s" % vertex)
    x+=2
    for edge in edges:
        G.add_node("%s" % edge)
        G.add_edge("%s" % vertex, "%s" % edge, weight = x)
        print("'%s' it connects with '%s'" % (vertex,edge))
# ---- END OF UNCHANGED CODE ----

# Create positions of all nodes and save them
pos = nx.spring_layout(G)

# Draw the graph according to node positions
nx.draw(G, pos, with_labels=True)

# Create edge labels
labels = {e: str(e) for e in G.edges}

# Draw edge labels according to node positions
nx.draw_networkx_edge_labels(G, pos, edge_labels=labels)

plt.show()

- vurmux