我正在尝试实现一个小例子，希望使用XSL作为转换器将文本文件中的内容转换为XML文件。我在SO上发现了这个示例-XSL-从文本文件创建格式良好的xml，并尝试实现相同的操作，但遇到了一些问题。
我正在使用相同的文本文件作为输入以及SO帖子答案中提到的XSL文件。这是我正在尝试使用的Java程序：
public class Parser {
public static void main(String[] args) {
String path="src/";
String text = path+"input.txt";
String xslt = path+"input.xsl";
String output = path+"output.xml";
System.setProperty("javax.xml.transform.TransformerFactory",
"net.sf.saxon.TransformerFactoryImpl");
try {
TransformerFactory tf = TransformerFactory.newInstance();
Transformer tr = tf.newTransformer(new StreamSource(xslt));
tr.transform(new StreamSource(text), new StreamResult(
new FileOutputStream(output)));
System.out.println("Output to " + output);
} catch (Exception e) {
System.out.println(e);
e.printStackTrace();
}
}
}
我得到的异常是：
Error on line 1 column 1 of input.txt:
SXXP0003: Error reported by XML parser: Content is not allowed in prolog.
net.sf.saxon.trans.XPathException: org.xml.sax.SAXParseException: Content is not allowed in prolog.
net.sf.saxon.trans.XPathException: org.xml.sax.SAXParseException: Content is not allowed in prolog.
at net.sf.saxon.event.Sender.sendSAXSource(Sender.java:418)
at net.sf.saxon.event.Sender.send(Sender.java:214)
at net.sf.saxon.event.Sender.send(Sender.java:50)
at net.sf.saxon.Controller.transform(Controller.java:1611)
at three.Parser.main(Parser.java:21)
Caused by: org.xml.sax.SAXParseException: Content is not allowed in prolog.
at com.sun.org.apache.xerces.internal.util.ErrorHandlerWrapper.createSAXParseException(ErrorHandlerWrapper.java:195)
at com.sun.org.apache.xerces.internal.util.ErrorHandlerWrapper.fatalError(ErrorHandlerWrapper.java:174)
at com.sun.org.apache.xerces.internal.impl.XMLErrorReporter.reportError(XMLErrorReporter.java:388)
at com.sun.org.apache.xerces.internal.impl.XMLScanner.reportFatalError(XMLScanner.java:1427)
at com.sun.org.apache.xerces.internal.impl.XMLDocumentScannerImpl$PrologDriver.next(XMLDocumentScannerImpl.java:1036)
at com.sun.org.apache.xerces.internal.impl.XMLDocumentScannerImpl.next(XMLDocumentScannerImpl.java:647)
at com.sun.org.apache.xerces.internal.impl.XMLNSDocumentScannerImpl.next(XMLNSDocumentScannerImpl.java:140)
at com.sun.org.apache.xerces.internal.impl.XMLDocumentFragmentScannerImpl.scanDocument(XMLDocumentFragmentScannerImpl.java:511)
at com.sun.org.apache.xerces.internal.parsers.XML11Configuration.parse(XML11Configuration.java:808)
at com.sun.org.apache.xerces.internal.parsers.XML11Configuration.parse(XML11Configuration.java:737)
at com.sun.org.apache.xerces.internal.parsers.XMLParser.parse(XMLParser.java:119)
at com.sun.org.apache.xerces.internal.parsers.AbstractSAXParser.parse(AbstractSAXParser.java:1205)
at com.sun.org.apache.xerces.internal.jaxp.SAXParserImpl$JAXPSAXParser.parse(SAXParserImpl.java:522)
at net.sf.saxon.event.Sender.sendSAXSource(Sender.java:404)
... 4 more
看起来我不能在我的程序中使用文本文件作为输入。有人可以帮我解决这个问题吗？
更新：
我已经按照Martin的建议使用Saxon S9 API（使用Jar - saxon9he.jar）解决了这个问题，以下是可行的JAVA代码。
import java.io.File;
import javax.xml.transform.stream.StreamSource;
import net.sf.saxon.s9api.Processor;
import net.sf.saxon.s9api.QName;
import net.sf.saxon.s9api.SaxonApiException;
import net.sf.saxon.s9api.Serializer;
import net.sf.saxon.s9api.XsltCompiler;
import net.sf.saxon.s9api.XsltExecutable;
import net.sf.saxon.s9api.XsltTransformer;
public class Parser {
public static void main(String[] args) throws SaxonApiException {
Processor proc = new Processor(false);
XsltCompiler comp = proc.newXsltCompiler();
XsltExecutable exp = comp.compile(new StreamSource(new File(
"src/input.xsl")));
Serializer out = new Serializer();
out.setOutputProperty(Serializer.Property.METHOD, "xml");
out.setOutputProperty(Serializer.Property.INDENT, "yes");
out.setOutputFile(new File("src/output.xml"));
XsltTransformer trans = exp.load();
trans.setInitialTemplate(new QName("main"));
trans.setDestination(out);
trans.transform();
System.out.println("Output written to text file");
}
}