我想输出两个不同的视图(一个作为将发送电子邮件的字符串,另一个作为显示给用户的页面)。
在ASP.NET MVC Beta中是否可能实现?
我尝试了多个示例:
1. 在ASP.NET MVC Beta中呈现 RenderPartial 为字符串
如果我使用此示例,则会收到“无法在HTTP标头已发送后重定向。”的错误信息。
如果我使用此示例,则似乎无法执行 redirectToAction,因为它试图呈现可能不存在的视图。如果我返回视图,则完全混乱,并且看起来一点也不正确。
是否有人对我遇到的这些问题有任何想法或解决方案,或者有更好的建议?
非常感谢!
下面是一个示例。 我正在尝试创建 GetViewForEmail 方法:
public ActionResult OrderResult(string ref)
{
//Get the order
Order order = OrderService.GetOrder(ref);
//The email helper would do the meat and veg by getting the view as a string
//Pass the control name (OrderResultEmail) and the model (order)
string emailView = GetViewForEmail("OrderResultEmail", order);
//Email the order out
EmailHelper(order, emailView);
return View("OrderResult", order);
}
Tim Scott的被接受的答案(稍加修改和格式化):
public virtual string RenderViewToString(
ControllerContext controllerContext,
string viewPath,
string masterPath,
ViewDataDictionary viewData,
TempDataDictionary tempData)
{
Stream filter = null;
ViewPage viewPage = new ViewPage();
//Right, create our view
viewPage.ViewContext = new ViewContext(controllerContext, new WebFormView(viewPath, masterPath), viewData, tempData);
//Get the response context, flush it and get the response filter.
var response = viewPage.ViewContext.HttpContext.Response;
response.Flush();
var oldFilter = response.Filter;
try
{
//Put a new filter into the response
filter = new MemoryStream();
response.Filter = filter;
//Now render the view into the memorystream and flush the response
viewPage.ViewContext.View.Render(viewPage.ViewContext, viewPage.ViewContext.HttpContext.Response.Output);
response.Flush();
//Now read the rendered view.
filter.Position = 0;
var reader = new StreamReader(filter, response.ContentEncoding);
return reader.ReadToEnd();
}
finally
{
//Clean up.
if (filter != null)
{
filter.Dispose();
}
//Now replace the response filter
response.Filter = oldFilter;
}
}
使用示例
假设从控制器调用以获取订单确认电子邮件并传递Site.Master位置。
string myString = RenderViewToString(this.ControllerContext, "~/Views/Order/OrderResultEmail.aspx", "~/Views/Shared/Site.Master", this.ViewData, this.TempData);