如何将部分视图呈现为字符串

61

我有以下代码:

public ActionResult SomeAction()
{
    return new JsonpResult
    {
        Data = new { Widget = "some partial html for the widget" }
    };
}

我想修改它,以便我可以拥有

public ActionResult SomeAction()
{
    // will render HTML that I can pass to the JSONP result to return.
    var partial = RenderPartial(viewModel); 
    return new JsonpResult
    {
        Data = new { Widget = partial }
    };
}

这种情况可行吗?有人能解释一下怎么做吗?

注意,我在发布解决方案之前编辑了问题。


对于所有的答案 - 如果你试图从另一个控制器呈现视图,你必须完全指定视图名称 "~/Views/<Controller>/<ViewName>.cshtml" - drzaus
10个回答

64

我选择了像下面这样的扩展方法,用于 ASP.NET MVC 4 应用程序。我认为它比我看到的一些建议更简单:

public static class ViewExtensions
{
    public static string RenderToString(this PartialViewResult partialView)
    {
        var httpContext = HttpContext.Current;

        if (httpContext == null)
        {
            throw new NotSupportedException("An HTTP context is required to render the partial view to a string");
        }

        var controllerName = httpContext.Request.RequestContext.RouteData.Values["controller"].ToString();

        var controller = (ControllerBase)ControllerBuilder.Current.GetControllerFactory().CreateController(httpContext.Request.RequestContext, controllerName);

        var controllerContext = new ControllerContext(httpContext.Request.RequestContext, controller);

        var view = ViewEngines.Engines.FindPartialView(controllerContext, partialView.ViewName).View;

        var sb = new StringBuilder();

        using (var sw = new StringWriter(sb))
        {
            using (var tw = new HtmlTextWriter(sw))
            {
                view.Render(new ViewContext(controllerContext, view, partialView.ViewData, partialView.TempData, tw), tw);
            }
        }

        return sb.ToString();
    }
}

它使我能够做到以下几点:

var html = PartialView("SomeView").RenderToString();

此外,这种方法会将任何ModelViewBag和其他视图数据保留在视图中。


1
我喜欢扩展方法的想法,因为你可以获得PartialView方法的语法高亮和编辑时错误检查,即当找到具有该名称的视图时,视图名称会改变颜色。 - William T. Mallard
@ted-nyberg 迁移到了一个 MVC 5 应用程序,但是这个扩展出现了以下错误信息:“值不能为 null。参数名:controllerContext”,有什么解决方法吗?谢谢。 - Miguel

35

这是一个稍微修改过的答案,可以正常使用:

public static string RenderPartialToString(string controlName, object viewData)
{
    ViewPage viewPage = new ViewPage() { ViewContext = new ViewContext() };

    viewPage.ViewData = new ViewDataDictionary(viewData);
    viewPage.Controls.Add(viewPage.LoadControl(controlName));

    StringBuilder sb = new StringBuilder();
    using (StringWriter sw = new StringWriter(sb))
    {
        using (HtmlTextWriter tw = new HtmlTextWriter(sw))
        {
            viewPage.RenderControl(tw);
        }
    }

    return sb.ToString();
}

用法:

string ret = RenderPartialToString("~/Views/MyController/MyPartial.ascx", model);

5
这对我很有效。然而,如果我在传递给该方法的局部视图中添加RenderPartial,那么在调用RenderControl时我开始收到一个异常:"值不能为空。参数名:view"。 - Pete Nelson
5
对我没用,我使用的是 Razor 视图引擎,看起来这只适用于 ascx 用户控件而不是部分 cshtml 视图。我在这里发布了自己使用 Razor 工作的版本:http://stackoverflow.com/questions/5532345/mvc-render-to-string-in-the-controller-or-else-were/8677839#comment10788063_8677839 - Nestor

12

DaveDev的答案对我很有用,但是当部分视图调用另一个部分时,我会遇到“值不能为null。参数名称:view”

经过搜索,我做了一种变体,参考以下链接似乎也可以正常工作。

 public static string RenderPartialToString(string viewName, object model, ControllerContext ControllerContext)
    {
        if (string.IsNullOrEmpty(viewName))
            viewName = ControllerContext.RouteData.GetRequiredString("action");
        ViewDataDictionary ViewData = new ViewDataDictionary();
        TempDataDictionary TempData = new TempDataDictionary();
        ViewData.Model = model;

        using (StringWriter sw = new StringWriter())
        {
            ViewEngineResult viewResult = ViewEngines.Engines.FindPartialView(ControllerContext, viewName);
            ViewContext viewContext = new ViewContext(ControllerContext, viewResult.View, ViewData, TempData, sw);
            viewResult.View.Render(viewContext, sw);

            return sw.GetStringBuilder().ToString();
        }

    }

使用方法:

String result = MVCHelpers.RenderPartialToString("PartialViewHere", Model, ControllerContext)

7
你可以创建能够将视图呈现为字符串的扩展。
public static class RenderPartialToStringExtensions
{
    /// <summary>
    /// render PartialView and return string
    /// </summary>
    /// <param name="context"></param>
    /// <param name="partialViewName"></param>
    /// <param name="model"></param>
    /// <returns></returns>
    public static string RenderPartialToString(this ControllerContext context, string partialViewName, object model)
    {
        return RenderPartialToStringMethod(context, partialViewName, model);
    }

    /// <summary>
    /// render PartialView and return string
    /// </summary>
    /// <param name="context"></param>
    /// <param name="partialViewName"></param>
    /// <param name="viewData"></param>
    /// <param name="tempData"></param>
    /// <returns></returns>
    public static string RenderPartialToString(ControllerContext context, string partialViewName, ViewDataDictionary viewData, TempDataDictionary tempData)
    {
        return RenderPartialToStringMethod(context, partialViewName, viewData, tempData);
    }

    public static string RenderPartialToStringMethod(ControllerContext context, string partialViewName, ViewDataDictionary viewData, TempDataDictionary tempData)
    {
        ViewEngineResult result = ViewEngines.Engines.FindPartialView(context, partialViewName);

        if (result.View != null)
        {
            StringBuilder sb = new StringBuilder();
            using (StringWriter sw = new StringWriter(sb))
            {
                using (HtmlTextWriter output = new HtmlTextWriter(sw))
                {
                    ViewContext viewContext = new ViewContext(context, result.View, viewData, tempData, output);
                    result.View.Render(viewContext, output);
                }
            }

            return sb.ToString();
        }
        return String.Empty;
    }

    public static string RenderPartialToStringMethod(ControllerContext context, string partialViewName, object model)
    {
        ViewDataDictionary viewData = new ViewDataDictionary(model);
        TempDataDictionary tempData = new TempDataDictionary();
        return RenderPartialToStringMethod(context, partialViewName, viewData, tempData);
    }
}

然后将其应用到实际操作中

[HttpPost]
public ActionResult GetTreeUnit(string id)
{
    int _id = id.ExtractID();
    string render = ControllerContext.RenderPartialToString("SomeView");
    return Json(new { data = render });
}

3

完美运行(仅需要视图名称)
* 对于参数,您可以使用模型
* 也可以从视图中调用此函数

视图端或调用端

BuyOnlineCartMaster ToInvoice1 = new BuyOnlineCartMaster(); // for passing parameters
ToInvoice1.CartID = 1;

string HtmlString = RenderPartialViewToString("PartialInvoiceCustomer", ToInvoice1);

生成HTML的函数

public class BuyOnlineCartMaster
{
        public int CartID { get; set; }
}

 public static string RenderPartialViewToString(string viewName, object model)
 {    
     using (var sw = new StringWriter())
            {
                BuyOnlineController controller = new BuyOnlineController(); // instance of the required controller (you can pass this as a argument if needed)

                // Create an MVC Controller Context
                var wrapper = new HttpContextWrapper(System.Web.HttpContext.Current);

                RouteData routeData = new RouteData();

                routeData.Values.Add("controller", controller.GetType().Name
                                                            .ToLower()
                                                            .Replace("controller", ""));

                controller.ControllerContext = new ControllerContext(wrapper, routeData, controller);

                controller.ViewData.Model = model;

                var viewResult = ViewEngines.Engines.FindPartialView(controller.ControllerContext, viewName);

                var viewContext = new ViewContext(controller.ControllerContext, viewResult.View, controller.ViewData, controller.TempData, sw);
                viewResult.View.Render(viewContext, sw);

                return sw.ToString();
            }
   }

部分视图页面

@{ 
    var ModelContents = (Common.BuyOnlineCartMaster)ViewData.Model;


}

Your cart id : @(ModelContents.CartID)

2
您可以直接使用以下代码实现此功能:

var partial = new HtmlString(Html.Partial("_myPartial", Model).ToString());

2
我无法获取Html.Partial。 - Machado
1
据我所知,Html.Partial不能直接在控制器中使用。您是如何让这行代码工作的? - Miguel
抱歉,您是正确的,我们是在 Razor 视图的 @{ } 块中使用该行代码,而不是直接在控制器中。也许您的控制器可以返回一个使用该代码的局部视图。 - Dan P

1
public virtual string RenderPartialViewToString(string viewName, object viewmodel)
        {
            if (string.IsNullOrEmpty(viewName))
            {
                viewName = this.ControllerContext.RouteData.GetRequiredString("action");
            }

            ViewData.Model = viewmodel;

            using (var sw = new StringWriter())
            {
                ViewEngineResult viewResult = System.Web.Mvc.ViewEngines.Engines.FindPartialView(this.ControllerContext, viewName);
                var viewContext = new ViewContext(this.ControllerContext, viewResult.View, this.ViewData, this.TempData, sw);
                viewResult.View.Render(viewContext, sw);
                viewResult.ViewEngine.ReleaseView(ControllerContext, viewResult.View);

                return sw.GetStringBuilder().ToString();
            }
        }

1

虽然这篇文章比较旧,但我认为你把它想得太复杂了。

为什么不使用return PartialView("<my partial>", model);,它会返回你想要的字符串。

只需将Get/Post方法设置为IActionResult,就像JsonResultPartialResult和其他继承自ActionResult一样,你可以发送任何东西,包括JsonResult

  [HttpPost]
  public IActionResult CheckForContent(string id, string type){
    try{
       
       if(type = "something"){
          return Json(new {
             success = true,
             myProp = "this prop"       
          });
       } else {
          MyViewModel model = new MyViewModel();
          model.Content = _service.GetContent(new GetContentRequest(){ id = id }
          return PartialView("<my partial>", model);
    } catch(Exception ex){
       _logger.LogError(ex.Message);
       return Json(new { success = false }
    }
  }

Ajax:
   $.ajax({
      url: '/CheckForContent',
      type: 'POST',
      cache: false,
      contentType: false,
      processData: false,
      success: function (result) {
         if(!result && !result.success){
            console.log("Failed to load");
         } else if(result && result.success){
            $('#MyProp').val(result.myProp);
         } else {
            $('#MyContainer').html(result);
         }
      },
   });

1

大卫,

同一主题的变体(mvc v1.0):

        protected static string RenderPartialToString(Controller controller, string partialName, object model)
    {
        var vd = new ViewDataDictionary(controller.ViewData);
        var vp = new ViewPage
        {
            ViewData = vd,
            ViewContext = new ViewContext(),
            Url = new UrlHelper(controller.ControllerContext.RequestContext)
        };

        ViewEngineResult result = ViewEngines
                                  .Engines
                                  .FindPartialView(controller.ControllerContext, partialName);

        if (result.View == null)
        {
            throw new InvalidOperationException(
            string.Format("The partial view '{0}' could not be found", partialName));
        }
        var partialPath = ((WebFormView)result.View).ViewPath;

        vp.ViewData.Model = model;

        Control control = vp.LoadControl(partialPath);
        vp.Controls.Add(control);

        var sb = new StringBuilder();

        using (var sw = new StringWriter(sb))
        {
            using (var tw = new HtmlTextWriter(sw))
            {
                vp.RenderControl(tw);
            }
        }
        return sb.ToString();
    }

在控制器中的使用方法:

        public string GetLocationHighlites()
    {
        IBlockData model = WebPagesMapper.GetLocationHighlites();
        // **this** being the controoler instance
        // LocationPartial.ascx can be defined in shared or in view folder
        return RenderPartialToString(**this**,"LocationPartial", model);
    }

0

对我来说,现有的答案都不起作用,因为我正在使用ASP.NET Core 6.0,所以我自己编写了一个。

async Task<string> getPartialViewHtml(string viewName)
{
    var builder = new StringBuilder();
    var writer  = new StringWriter(builder);
    var content = await Html.PartialAsync(viewName);

    content.WriteTo(writer, HtmlEncoder.Default);

    var output = builder.ToString();

    return output;
}

示例用法如下:

var viewHtml = await getPartialViewHtml("PartialViewNameGoesHere");

网页内容由stack overflow 提供, 点击上面的
可以查看英文原文,
原文链接