如何使用Swift检查iPhone型号

Question

如何在Swift中检查iPhone型号（例如iPhone 4 / iPhone 5）。使用以下代码，我可以检查它是否为iPod或iPhone。

let iphoneModel = UIDevice.currentDevice().model
if (iphoneModel == "iPhone"){
        println("Iphone 4")
    }

我需要具体知道是哪个iPhone型号。

- Saqib Omer

---

请查看以下链接：https://dev59.com/g18e5IYBdhLWcg3wJnyl - Lie-An

请查看此链接：https://dev59.com/g18e5IYBdhLWcg3wJnyl - nikhil84

Answer 1

请使用以下代码。（参考自）

enum UIUserInterfaceIdiom : Int
{
    case Unspecified
    case Phone
    case Pad
}

struct ScreenSize
{
    static let SCREEN_WIDTH         = UIScreen.mainScreen().bounds.size.width
    static let SCREEN_HEIGHT        = UIScreen.mainScreen().bounds.size.height
    static let SCREEN_MAX_LENGTH    = max(ScreenSize.SCREEN_WIDTH, ScreenSize.SCREEN_HEIGHT)
    static let SCREEN_MIN_LENGTH    = min(ScreenSize.SCREEN_WIDTH, ScreenSize.SCREEN_HEIGHT)
}

struct DeviceType
{
    static let IS_IPHONE_4_OR_LESS  = UIDevice.currentDevice().userInterfaceIdiom == .Phone && ScreenSize.SCREEN_MAX_LENGTH < 568.0
    static let IS_IPHONE_5          = UIDevice.currentDevice().userInterfaceIdiom == .Phone && ScreenSize.SCREEN_MAX_LENGTH == 568.0
    static let IS_IPHONE_6          = UIDevice.currentDevice().userInterfaceIdiom == .Phone && ScreenSize.SCREEN_MAX_LENGTH == 667.0
    static let IS_IPHONE_6P         = UIDevice.currentDevice().userInterfaceIdiom == .Phone && ScreenSize.SCREEN_MAX_LENGTH == 736.0
    static let IS_IPAD              = UIDevice.currentDevice().userInterfaceIdiom == .Pad && ScreenSize.SCREEN_MAX_LENGTH == 1024.0
}

并将其用作：

if DeviceType.IS_IPHONE_6P {
            println("IS_IPHONE_6P")
}

- Shardul

---

我专门为此创建了一个Swift类：https://github.com/mikeKane/findThatModel - mKane

Answer 2

SWIFT 3

enum UIUserInterfaceIdiom : Int
{
    case Unspecified
    case Phone
    case Pad
}

struct ScreenSize
{
    static let SCREEN_WIDTH         = UIScreen.main.bounds.size.width
    static let SCREEN_HEIGHT        = UIScreen.main.bounds.size.height
    static let SCREEN_MAX_LENGTH    = max(ScreenSize.SCREEN_WIDTH, ScreenSize.SCREEN_HEIGHT)
    static let SCREEN_MIN_LENGTH    = min(ScreenSize.SCREEN_WIDTH, ScreenSize.SCREEN_HEIGHT)
}

struct DeviceType
{
    static let IS_IPHONE_4_OR_LESS  = UIDevice.current.userInterfaceIdiom == .phone && ScreenSize.SCREEN_MAX_LENGTH < 568.0
    static let IS_IPHONE_5          = UIDevice.current.userInterfaceIdiom == .phone && ScreenSize.SCREEN_MAX_LENGTH == 568.0
    static let IS_IPHONE_6          = UIDevice.current.userInterfaceIdiom == .phone && ScreenSize.SCREEN_MAX_LENGTH == 667.0
    static let IS_IPHONE_6P         = UIDevice.current.userInterfaceIdiom == .phone && ScreenSize.SCREEN_MAX_LENGTH == 736.0
    static let IS_IPAD              = UIDevice.current.userInterfaceIdiom == .pad && ScreenSize.SCREEN_MAX_LENGTH == 1024.0
}

并且用于使用。

if DeviceType.IS_IPHONE_6P{
    print("IS_IPHONE_6P")
}

- Ahmed Safadi

Answer 3

支持Swift 4 + iPhone Xr、Xs、Xs Max

import UIKit

enum UIUserInterfaceIdiom : Int {
    case Unspecified
    case phone
    case pad
}

struct ScreenSize {
    static let screenWidth = UIScreen.main.bounds.size.width
    static let screenHeight = UIScreen.main.bounds.size.height
    static let screenMaxLength = max(ScreenSize.screenWidth, ScreenSize.screenHeight)
    static let screenMinLength = min(ScreenSize.screenWidth, ScreenSize.screenHeight)
}

struct DeviceType {
    static let iPhone4OrLess  = UIDevice.current.userInterfaceIdiom == .phone && ScreenSize.screenMaxLength < 568.0
    static let iPhoneSE = UIDevice.current.userInterfaceIdiom == .phone && ScreenSize.screenMaxLength == 568.0
    static let iPhone8 = UIDevice.current.userInterfaceIdiom == .phone && ScreenSize.screenMaxLength == 667.0
    static let iPhone8Plus = UIDevice.current.userInterfaceIdiom == .phone && ScreenSize.screenMaxLength == 736.0
    static let iPhoneXr = UIDevice.current.userInterfaceIdiom == .phone && ScreenSize.screenMaxLength == 896.0
    static let iPhoneXs = UIDevice.current.userInterfaceIdiom == .phone && ScreenSize.screenMaxLength == 812.0
    static let iPhoneXsMax = UIDevice.current.userInterfaceIdiom == .phone && ScreenSize.screenMaxLength == 896.0
    static let iPad = UIDevice.current.userInterfaceIdiom == .phone && ScreenSize.screenMaxLength == 1024.0
}

同时使用：

 if DeviceType.iPhoneXsMax {
      print("is Max here")
 }

- Nicolas.B

Answer 4

Swift 4:

enum UIUserInterfaceIdiom : Int
{
  case Unspecified
  case Phone
  case Pad
}

struct ScreenSize
{
  static let SCREEN_WIDTH         = UIScreen.main.bounds.size.width
  static let SCREEN_HEIGHT        = UIScreen.main.bounds.size.height
  static let SCREEN_MAX_LENGTH    = max(ScreenSize.SCREEN_WIDTH, ScreenSize.SCREEN_HEIGHT)
  static let SCREEN_MIN_LENGTH    = min(ScreenSize.SCREEN_WIDTH, ScreenSize.SCREEN_HEIGHT)
}

struct DeviceType
{
  static let IS_IPHONE_4_OR_LESS  = UIDevice.current.userInterfaceIdiom == .phone && ScreenSize.SCREEN_MAX_LENGTH < 568.0
  static let IS_IPHONE_5          = UIDevice.current.userInterfaceIdiom == .phone && ScreenSize.SCREEN_MAX_LENGTH == 568.0
  static let IS_IPHONE_6          = UIDevice.current.userInterfaceIdiom == .phone && ScreenSize.SCREEN_MAX_LENGTH == 667.0
  static let IS_IPHONE_6P         = UIDevice.current.userInterfaceIdiom == .phone && ScreenSize.SCREEN_MAX_LENGTH == 736.0
  static let IS_IPAD              = UIDevice.current.userInterfaceIdiom == .pad && ScreenSize.SCREEN_MAX_LENGTH == 1024.0
}

例子：

 if DeviceType.IS_IPHONE_5 {
      //TODO:
 }

- Bogdan Bystritskiy