如何以编程方式检查iPad的版本/型号

13
有没有一种方法可以检查iPad的版本/型号(即iPad 1/2/3)?我在我的iPad界面中使用了一些透明度和多个叠加层。虽然在iPad 2上工作得很好,但在iPad 1上却不能给用户带来良好的体验。因此,我想在iPad 1上去掉透明度,但找不到知道我正在处理哪种iPad的方法。
有没有诀窍来区分iPad 1和更高版本,这些版本具有更强大的图形处理器(即目前的iPad 2 + 3)?
我读到在Web浏览器中可能是可行的,因此在代码中应该有获取型号号码的方法。
3个回答

15

我希望这正是你所需要的:

  NSString *platform = [self platform];

    if ([platform isEqualToString:@"iPhone1,1"])    return @"iPhone 1G";
    if ([platform isEqualToString:@"iPhone1,2"])    return @"iPhone 3G";
    if ([platform isEqualToString:@"iPhone2,1"])    return @"iPhone 3GS";
    if ([platform isEqualToString:@"iPhone3,1"])    return @"iPhone 4";
    if ([platform isEqualToString:@"iPhone3,3"])    return @"Verizon iPhone 4";
    if ([platform isEqualToString:@"iPhone4,1"])    return @"iPhone 4S";
    if ([platform isEqualToString:@"iPhone5,1"])    return @"iPhone 5 (GSM)";
    if ([platform isEqualToString:@"iPhone5,2"])    return @"iPhone 5 (GSM+CDMA)";
    if ([platform isEqualToString:@"iPhone5,3"])    return @"iPhone 5c (GSM)";
    if ([platform isEqualToString:@"iPhone5,4"])    return @"iPhone 5c (Global)";
    if ([platform isEqualToString:@"iPhone6,1"])    return @"iPhone 5s (GSM)";
    if ([platform isEqualToString:@"iPhone6,2"])    return @"iPhone 5s (Global)";
    if ([platform isEqualToString:@"iPhone7,1"])    return @"iPhone 6+";
    if ([platform isEqualToString:@"iPhone7,2"])    return @"iPhone 6";

    if ([platform isEqualToString:@"iPod1,1"])      return @"iPod Touch 1G";
    if ([platform isEqualToString:@"iPod2,1"])      return @"iPod Touch 2G";
    if ([platform isEqualToString:@"iPod3,1"])      return @"iPod Touch 3G";
    if ([platform isEqualToString:@"iPod4,1"])      return @"iPod Touch 4G";
    if ([platform isEqualToString:@"iPod5,1"])      return @"iPod Touch 5G";

    if ([platform isEqualToString:@"iPad1,1"])      return @"iPad";
    if ([platform isEqualToString:@"iPad2,1"])      return @"iPad 2 (WiFi)";
    if ([platform isEqualToString:@"iPad2,2"])      return @"iPad 2 (GSM)";
    if ([platform isEqualToString:@"iPad2,3"])      return @"iPad 2 (CDMA)";
    if ([platform isEqualToString:@"iPad2,4"])      return @"iPad 2 (WiFi)";
    if ([platform isEqualToString:@"iPad2,5"])      return @"iPad Mini (WiFi)";
    if ([platform isEqualToString:@"iPad2,6"])      return @"iPad Mini (GSM)";
    if ([platform isEqualToString:@"iPad2,7"])      return @"iPad Mini (GSM+CDMA)";
    if ([platform isEqualToString:@"iPad3,1"])      return @"iPad 3 (WiFi)";
    if ([platform isEqualToString:@"iPad3,2"])      return @"iPad 3 (GSM+CDMA)";
    if ([platform isEqualToString:@"iPad3,3"])      return @"iPad 3 (GSM)";
    if ([platform isEqualToString:@"iPad3,4"])      return @"iPad 4 (WiFi)";
    if ([platform isEqualToString:@"iPad3,5"])      return @"iPad 4 (GSM)";
    if ([platform isEqualToString:@"iPad3,6"])      return @"iPad 4 (GSM+CDMA)";
    if ([platform isEqualToString:@"iPad4,1"])      return @"iPad Air (WiFi)";
    if ([platform isEqualToString:@"iPad4,2"])      return @"iPad Air (Cellular)";
    if ([platform isEqualToString:@"iPad4,3"])      return @"iPad Air";
    if ([platform isEqualToString:@"iPad4,4"])      return @"iPad Mini 2 (WiFi)";
    if ([platform isEqualToString:@"iPad4,5"])      return @"iPad Mini 2 (Cellular)";
    if ([platform isEqualToString:@"iPad4,6"])      return @"iPad Mini 2 (Rev)";
    if ([platform isEqualToString:@"iPad4,7"])      return @"iPad Mini 3 (WiFi)";
    if ([platform isEqualToString:@"iPad4,8"])      return @"iPad Mini 3 (A1600)";
    if ([platform isEqualToString:@"iPad4,9"])      return @"iPad Mini 3 (A1601)";
    if ([platform isEqualToString:@"iPad5,3"])      return @"iPad Air 2 (WiFi)";
    if ([platform isEqualToString:@"iPad5,4"])      return @"iPad Air 2 (Cellular)";

    if ([platform isEqualToString:@"i386"])         return @"Simulator";
    if ([platform isEqualToString:@"x86_64"])       return @"Simulator";

这段代码来源于:https://gist.github.com/1323251


1
我不会真的依赖这段代码来做任何事情,只是用于调试;它相当低级且缺乏明确的文档说明。还有其他方法可以实现OP所需的功能。 - Ash Furrow
1
-1 #1:与OP的问题相比有些过度,#2“正是为了这样的代码才发明了数组!” - Michael Robinson
新款iPhone会是iPhone5,1吗?这个猜测是否安全呢? - simongking

12

我检查相机是否存在,但iPad 1上没有相机。由于2和3具有类似的CPU性能,这对我很有效(我处于类似的情况,但与内存有关)。

if ([UIImagePickerController isSourceTypeAvailable: UIImagePickerControllerSourceTypeCamera])
    NSLog(@"iPad 2 or 3");
else
    NSLog(@"iPad 1");

2
这似乎是最简单的,可以完成工作! - Luuk D. Jansen

1

Erica Sadun为此编写了一些实用工具,作为UIDevice的类别。可在她的Github存储库uidevice-extension上获得。UIDevice-Hardware.h/m特别适合您的需求。支持iPhone 5。


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