我一直在谷歌和Stack Exchange上搜索正确的答案,但似乎找不到。我有一个通过弹出式segue呈现的弹出视图,当弹出视图内部的按钮被点击时,我希望它被关闭并显示一个UIAlert。以下是迄今为止我从其他答案中收集到的代码,但不起作用:
- (void)prepareForSegue:(UIStoryboardSegue *)segue sender:(id)sender
{
if ([segue.identifier isEqualToString:@"popOverSegue"]) {
if ([segue isKindOfClass:[UIStoryboardPopoverSegue class]]) {
UIStoryboardPopoverSegue *popoverSegue = (UIStoryboardPopoverSegue *)segue;
self.myPopoverController = popoverSegue.popoverController;
}
}
}
- (void)methodThatShouldCauseMyPopoverToCloseAnimated:(BOOL)animated
{
[self.myPopoverController dismissPopoverAnimated:animated];
NSLog(@"Dismissed");
}
-(IBAction)presentPopoverView:(id)sender {
if (!popOverViewIsShown){
[self performSegueWithIdentifier:@"popOverSegue" sender:self];
popOverViewIsShown = YES;
}else {
[self methodThatShouldCauseMyPopoverToCloseAnimated:YES];
popOverViewIsShown = NO;
}
}
- (IBAction)logoutMethod:(id)sender {
[self methodThatShouldCauseMyPopoverToCloseAnimated:YES];
UIAlertView *alert = [[UIAlertView alloc] initWithTitle:@"Logout"
message:@"Are you sure?"
delegate:self
cancelButtonTitle:@"Cancel"
otherButtonTitles:@"OK", nil];
alert.tag = 0;
[alert show];
}
我怀疑当我调用methodThatShouldCauseMyPopoverToClose
时,myPopoverController
等于nil。 有什么建议吗?非常感谢! :)