尽管我已经找到了一个解决方案，但我认为我应该发布这个问题，因为当我搜索时，没有现成的Java实现。
使用HSV而不是RGB允许生成具有相同饱和度和亮度的颜色（这正是我想要的）。
Google App Engine不允许使用java.awt.Color，因此无法执行以下操作来在HSV和RGB之间进行转换:
Color c = Color.getHSBColor(hue, saturation, value);
String rgb = Integer.toHexString(c.getRGB());
编辑：根据Nick Johnson的评论，我移动了我的答案。
Ex animo，- Alexander。
我对颜色数学一无所知，但是我可以提供这个代码的另一种结构作为替代方案。这个结构让我感到舒适，因为它让我清楚地看到每个6种情况只是一个不同的值、t和p的排列组合。(此外，我对长长的if-else链有一种非理性的恐惧。)
public static String hsvToRgb(float hue, float saturation, float value) {
int h = (int)(hue * 6);
float f = hue * 6 - h;
float p = value * (1 - saturation);
float q = value * (1 - f * saturation);
float t = value * (1 - (1 - f) * saturation);
switch (h) {
case 0: return rgbToString(value, t, p);
case 1: return rgbToString(q, value, p);
case 2: return rgbToString(p, value, t);
case 3: return rgbToString(p, q, value);
case 4: return rgbToString(t, p, value);
case 5: return rgbToString(value, p, q);
default: throw new RuntimeException("Something went wrong when converting from HSV to RGB. Input was " + hue + ", " + saturation + ", " + value);
}
}
public static String rgbToString(float r, float g, float b) {
String rs = Integer.toHexString((int)(r * 256));
String gs = Integer.toHexString((int)(g * 256));
String bs = Integer.toHexString((int)(b * 256));
return rs + gs + bs;
}
rgbToString 函数应该乘以 255 而不是 256 吗？否则，当 r 为 1.0 时，rs 将会变成十六进制的 100，这是错误的。 - devrobf您应该使用 Oracle 提供的 HSBtoRGB 实现，将其源代码复制到您的项目中。java.awt.Color 是开源的。Peter Recore 和 Yngling 提供的算法不够稳健，会返回像“256, 256, 0”这样的非法 RGB 值，适用于某些输入。Oracle 的实现是稳健的，请使用它。
HSLToColor(float\[\] hsl)
And
[RGBToHSL(int r, int g, int b, float\[\] hsl)]
易于相互转换的方法！
例如：
float[] hsl = new float[]{1.5, 2.0, 1.5};
int color = ColorUtils.HSLToColor(hsl);
float[] hslStub = new float[3];
float[] hslFromColor = ColorUtils.colorToHSL(color, hslStub);
public static String hsvToRgb(float hue, float saturation, float value) {
float r, g, b;
int h = (int)(hue * 6);
float f = hue * 6 - h;
float p = value * (1 - saturation);
float q = value * (1 - f * saturation);
float t = value * (1 - (1 - f) * saturation);
if (h == 0) {
r = value;
g = t;
b = p;
} else if (h == 1) {
r = q;
g = value;
b = p;
} else if (h == 2) {
r = p;
g = value;
b = t;
} else if (h == 3) {
r = p;
g = q;
b = value;
} else if (h == 4) {
r = t;
g = p;
b = value;
} else if (h <= 6) {
r = value;
g = p;
b = q;
} else {
throw new RuntimeException("Something went wrong when converting from HSV to RGB. Input was " + hue + ", " + saturation + ", " + value);
}
String rs = Integer.toHexString((int)(r * 255));
String gs = Integer.toHexString((int)(g * 255));
String bs = Integer.toHexString((int)(b * 255));
return rs + gs + bs;
}
| else if (h <= 6) {。转换应该是(r * 255)等，而不是* 256，因为颜色范围是0到255。 - ehartwell我的代码用于转换：
/**
* @param H
* 0-360
* @param S
* 0-100
* @param V
* 0-100
* @return color in hex string
*/
public static String hsvToRgb(float H, float S, float V) {
float R, G, B;
H /= 360f;
S /= 100f;
V /= 100f;
if (S == 0)
{
R = V * 255;
G = V * 255;
B = V * 255;
} else {
float var_h = H * 6;
if (var_h == 6)
var_h = 0; // H must be < 1
int var_i = (int) Math.floor((double) var_h); // Or ... var_i =
// floor( var_h )
float var_1 = V * (1 - S);
float var_2 = V * (1 - S * (var_h - var_i));
float var_3 = V * (1 - S * (1 - (var_h - var_i)));
float var_r;
float var_g;
float var_b;
if (var_i == 0) {
var_r = V;
var_g = var_3;
var_b = var_1;
} else if (var_i == 1) {
var_r = var_2;
var_g = V;
var_b = var_1;
} else if (var_i == 2) {
var_r = var_1;
var_g = V;
var_b = var_3;
} else if (var_i == 3) {
var_r = var_1;
var_g = var_2;
var_b = V;
} else if (var_i == 4) {
var_r = var_3;
var_g = var_1;
var_b = V;
} else {
var_r = V;
var_g = var_1;
var_b = var_2;
}
R = var_r * 255; // RGB results from 0 to 255
G = var_g * 255;
B = var_b * 255;
}
String rs = Integer.toHexString((int) (R));
String gs = Integer.toHexString((int) (G));
String bs = Integer.toHexString((int) (B));
if (rs.length() == 1)
rs = "0" + rs;
if (gs.length() == 1)
gs = "0" + gs;
if (bs.length() == 1)
bs = "0" + bs;
return "#" + rs + gs + bs;
}
tv.setBackgroundColor(Color.parseColor((ColorOperations.hsvToRgb(100, 100, 57))));
@Peter Recore的答案没有使用四舍五入。
更正确的方法可能是从java.awt.Color中复制内容，以下是Java 6中的样子：
public static int HSBtoRGB(float hue, float saturation, float brightness) {
int r = 0, g = 0, b = 0;
if (saturation == 0) {
r = g = b = (int) (brightness * 255.0f + 0.5f);
} else {
float h = (hue - (float)Math.floor(hue)) * 6.0f;
float f = h - (float)java.lang.Math.floor(h);
float p = brightness * (1.0f - saturation);
float q = brightness * (1.0f - saturation * f);
float t = brightness * (1.0f - (saturation * (1.0f - f)));
switch ((int) h) {
case 0:
r = (int) (brightness * 255.0f + 0.5f);
g = (int) (t * 255.0f + 0.5f);
b = (int) (p * 255.0f + 0.5f);
break;
case 1:
r = (int) (q * 255.0f + 0.5f);
g = (int) (brightness * 255.0f + 0.5f);
b = (int) (p * 255.0f + 0.5f);
break;
case 2:
r = (int) (p * 255.0f + 0.5f);
g = (int) (brightness * 255.0f + 0.5f);
b = (int) (t * 255.0f + 0.5f);
break;
case 3:
r = (int) (p * 255.0f + 0.5f);
g = (int) (q * 255.0f + 0.5f);
b = (int) (brightness * 255.0f + 0.5f);
break;
case 4:
r = (int) (t * 255.0f + 0.5f);
g = (int) (p * 255.0f + 0.5f);
b = (int) (brightness * 255.0f + 0.5f);
break;
case 5:
r = (int) (brightness * 255.0f + 0.5f);
g = (int) (p * 255.0f + 0.5f);
b = (int) (q * 255.0f + 0.5f);
break;
}
}
return 0xff000000 | (r << 16) | (g << 8) | (b << 0);
}
RGB rgb = new RGB(r, g, b);
float[] hsbColor = rgb.getHSB();
rgb = new RGB(hsbColor[0], hsbColor[1], hsbColor[2]);
(int,int,int)构造函数接受RGB，但(float,float,float)构造函数接受HSB。 - Andy Thomas我知道这是一个老问题，但我在这里看到的所有答案都将色调乘以6。这是错误的。我查看了维基百科文章，那里说你必须除以60。
这是我用Kotlin编写并测试过的代码示例：
fun hsvToRgb(hsv: FloatArray): IntArray {
val (hue, saturation, value) = hsv
val h: Int = (hue / 60).toInt()
val f = hue / 60 - h
val p = value * (1 - saturation)
val q = value * (1 - f * saturation)
val t = value * (1 - (1 - f) * saturation)
val rgb = when (h) {
0 -> floatArrayOf(value, t, p)
1 -> floatArrayOf(q, value, p)
2 -> floatArrayOf(p, value, t)
3 -> floatArrayOf(p, q, value)
4 -> floatArrayOf(t, p, value)
5, 6 -> floatArrayOf(value, p, q)
else -> throw Exception()
}.map { it * 255 }
val (r, g, b) = rgb
return intArrayOf(r.toInt(), g.toInt(), b.toInt())
}
这是我的 Java 实现
public static int[] hsvToRgb(float[] hsv) {
final float hue = hsv[0];
final float saturation = hsv[1];
final float value = hsv[2];
final int h = (int) hue / 60;
final float f = hue / 60 - h;
final float p = value * (1 - saturation);
final float q = value * (1 - f * saturation);
final float t = value * (1 - (1 - f) * saturation);
float[] rgb = switch (h) {
case 0 -> new float[]{value, t, p};
case 1 -> new float[]{q, value, p};
case 2 -> new float[]{p, value, t};
case 3 -> new float[]{p, q, value};
case 4 -> new float[]{t, p, value};
case 5, 6 -> new float[]{value, p, q};
default -> throw new IllegalStateException();
};
rgb[0] = rgb[0] * 255;
rgb[1] = rgb[1] * 255;
rgb[2] = rgb[2] * 255;
return new int[]{(int) rgb[0], (int) rgb[1], (int) rgb[2]};
}