我正在尝试将一个二进制文件读入到结构数组中。
下面的代码可以运行,但是一次只能处理一个元素,通过将每个新元素推入数组中。
struct FeaturePoint
{
FeaturePoint (const int & _cluster_id,
const float _x,
const float _y,
const float _a,
const float _b
) : cluster_id (_cluster_id), x(_x), y(_y), a(_a), b(_b) {}
FeaturePoint (){}
int cluster_id;
float x;
float y;
float a;
float b;
};
下面的代码可以运行,但是一次只能处理一个元素,通过将每个新元素推入数组中。
void LoadImageFeaturesFromBinaryFile(const char * FileName, std::vector<FeaturePoint>& features )
{
char strInputPath[200];
strcpy (strInputPath,"/mnt/imagesearch/tests/");
strcat (strInputPath,FileName);
strcat (strInputPath,".bin");
features.clear();
ifstream::pos_type size;
ifstream file (strInputPath, ios::in|ios::binary|ios::ate);
if (file.is_open())
{
size = file.tellg();
cout<< "this file size is : "<<size<<" for "<<strInputPath<<" " <<sizeof( FeaturePoint )<<endl;
file.seekg (0, ios::beg);
while (!file.eof())
{
try
{
FeaturePoint fp;
file.read( reinterpret_cast<char*>(&fp), sizeof( FeaturePoint ) );
features.push_back(fp);
}
catch (int e)
{ cout << "An exception occurred. Exception Nr. " << e << endl; }
}
sort (features.begin(), features.begin()+features.size(),CompareClusterIndexes);
file.close();
}
}
我希望通过一次性读取整个数组来加快速度,我认为应该像下面这样:
void LoadImageFeaturesFromBinaryFile(const char * FileName, std::vector<FeaturePoint>& features )
{
char strInputPath[200];
strcpy (strInputPath,"/mnt/imagesearch/tests/");
strcat (strInputPath,FileName);
strcat (strInputPath,".bin");
features.clear();
ifstream::pos_type size;
ifstream file (strInputPath, ios::in|ios::binary|ios::ate);
if (file.is_open())
{
size = file.tellg();
file.seekg (0, ios::beg);
features.reserve( size/sizeof( FeaturePoint ));
try
{
file.read( reinterpret_cast<char*>(&features), size );
}
catch (int e)
{ cout << "An exception occurred. Exception Nr. " << e << endl; }
sort (features.begin(), features.begin()+features.size(),CompareClusterIndexes);
file.close();
}
else cout << strInputPath<< " Unable to open file for Binary read"<<endl;
}
但读取数据导致了分段错误,我该怎么修复它?
std::string
代替strcat
。 - Fred Foo