TextInputEditText无法转换为TextInputLayout。

Question

我在我的活动中有这段代码

public class RegisterActivity extends AppCompatActivity {


private static final String TAG = RegisterActivity.class.getSimpleName();
private TextInputLayout mDisplayName;
private TextInputLayout mEmail;
private TextInputLayout mPassword;
private Button mCreateBtn;

private FirebaseAuth mAuth;
@Override
protected void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.activity_register);

    mAuth = FirebaseAuth.getInstance();

    mDisplayName = (TextInputLayout)findViewById(R.id.reg_display_name);
    mEmail = (TextInputLayout)findViewById(R.id.reg_email);
    mPassword = (TextInputLayout)findViewById(R.id.reg_password);
    mCreateBtn = (Button) findViewById(R.id.reg_create_btn);

    mCreateBtn.setOnClickListener(new View.OnClickListener() {
        @Override
        public void onClick(View view) {
            String displayName = mDisplayName.getEditText().getText().toString();
            String email = mEmail.getEditText().getText().toString();
            String password = mPassword.getEditText().getText().toString();

            registerUser(displayName,email,password);

        }


    });
}

private void registerUser(String displayName, String email, String password) {

   mAuth.signInWithEmailAndPassword(email,password)
           .addOnCompleteListener(this, new OnCompleteListener<AuthResult>() {
               @Override
               public void onComplete(@NonNull Task<AuthResult> task) {
                     if(task.isSuccessful()){
                         Intent mainIntent = new Intent(RegisterActivity.this,MainActivity.class);
                         startActivity(mainIntent);
                         finish();
                     }else{
                         Toast.makeText(RegisterActivity.this,"You got some error.",Toast.LENGTH_SHORT).show();
                     }
               }
           });

}


}

对应的XML代码如下：

<android.support.constraint.ConstraintLayout xmlns:android="http://schemas.android.com/apk/res/android"
    xmlns:app="http://schemas.android.com/apk/res-auto"
    xmlns:tools="http://schemas.android.com/tools"
    android:layout_width="match_parent"
    android:layout_height="match_parent"
    tools:context=".RegisterActivity">
    
    <android.support.design.widget.TextInputLayout
        android:id="@+id/textInputLayout2"
        android:layout_width="368dp"
        android:layout_height="wrap_content"
        android:layout_marginStart="8dp"
        android:layout_marginTop="8dp"
        app:layout_constraintStart_toStartOf="parent"
        app:layout_constraintTop_toTopOf="parent">
        
        <android.support.design.widget.TextInputEditText
            android:id="@+id/reg_display_name"
            android:layout_width="match_parent"
            android:layout_height="wrap_content"
            android:hint="hint"
            android:text="Display name" />
    </android.support.design.widget.TextInputLayout>
    
    <android.support.design.widget.TextInputLayout
        android:id="@+id/textInputLayout3"
        android:layout_width="368dp"
        android:layout_height="wrap_content"
        android:layout_marginStart="8dp"
        android:layout_marginTop="8dp"
        app:layout_constraintStart_toStartOf="parent"
        app:layout_constraintTop_toBottomOf="@+id/textInputLayout2">

        <android.support.design.widget.TextInputEditText
            android:id="@+id/reg_email"
            android:layout_width="match_parent"
            android:layout_height="wrap_content"
            android:hint="hint"
            android:text="Email" />
    </android.support.design.widget.TextInputLayout>
    
    <android.support.design.widget.TextInputLayout
        android:id="@+id/textInputLayout4"
        android:layout_width="368dp"
        android:layout_height="wrap_content"
        android:layout_marginStart="8dp"
        android:layout_marginTop="8dp"
        app:layout_constraintStart_toStartOf="parent"
        app:layout_constraintTop_toBottomOf="@+id/textInputLayout3">
    
        <android.support.design.widget.TextInputEditText
            android:id="@+id/reg_password"
            android:layout_width="match_parent"
            android:layout_height="wrap_content"
            android:hint="hint"
            android:text="Password" />
    </android.support.design.widget.TextInputLayout>

    <Button
        android:id="@+id/reg_create_btn"
        android:layout_width="wrap_content"
        android:layout_height="wrap_content"
        android:layout_marginTop="8dp"
        android:text="Create account"
        android:textAllCaps="false"
        app:layout_constraintTop_toBottomOf="@+id/textInputLayout4"
        tools:layout_editor_absoluteX="255dp" />
</android.support.constraint.ConstraintLayout>

当我运行该应用程序时，会出现以下信息：

Caused by: java.lang.ClassCastException: android.support.design.widget.TextInputEditText cannot be cast to android.support.design.widget.TextInputLayout

我也会给你 Gradle 文件，以防设计版本出现问题。

 apply plugin: 'com.android.application'

 android {
 compileSdkVersion 27
 defaultConfig {
    applicationId "theo.tziomakas.lapitchat"
    minSdkVersion 21
    targetSdkVersion 27
    versionCode 1
    versionName "1.0"
    testInstrumentationRunner 
    "android.support.test.runner.AndroidJUnitRunner"
  }
   buildTypes {
    release {
        minifyEnabled false
        proguardFiles getDefaultProguardFile('proguard-android.txt'), 'proguard-rules.pro'
    }
   }
}

dependencies {
implementation fileTree(dir: 'libs', include: ['*.jar'])
implementation 'com.android.support:appcompat-v7:27.1.1'
implementation 'com.android.support:design:27.1.1'
implementation 'com.android.support.constraint:constraint- 
layout:1.1.0'
implementation 'com.google.firebase:firebase-auth:11.6.0'
testImplementation 'junit:junit:4.12'
androidTestImplementation 'com.android.support.test:runner:1.0.2'
androidTestImplementation 
'com.android.support.test.espresso:espresso-core:3.0.2'
 }

 apply plugin: 'com.google.gms.google-services'

有什么解决那个异常的想法吗？

谢谢。 Theo.

- Theo

---

https://dev59.com/61kT5IYBdhLWcg3wB7Is#39229680 - IntelliJ Amiya

Answer 1

尝试转换为：

private TextInputEditText mDisplayName;
private TextInputEditText mEmail;
private TextInputEditText mPassword;


mDisplayName = (TextInputEditText)findViewById(R.id.reg_display_name);
mEmail = (TextInputEditText)findViewById(R.id.reg_email);
mPassword = (TextInputEditText)findViewById(R.id.reg_password);

- Tung Tran

---

无法工作。在 String displayName = mDisplayName.getEditText().getText().toString() 中找不到 getEditText()。 - Theo

mDisplayName is a TextInputEditText, so Replace to mDisplayName.getText().toString() - Tung Tran

Answer 2

试试这个：

public class RegisterActivity extends AppCompatActivity {


private static final String TAG = RegisterActivity.class.getSimpleName();
private TextInputEditText mDisplayName;
private TextInputEditText mEmail;
private TextInputEditText mPassword;
private Button mCreateBtn;

private FirebaseAuth mAuth;
@Override
protected void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.activity_register);

    mAuth = FirebaseAuth.getInstance();

    mDisplayName = (TextInputEditText)findViewById(R.id.reg_display_name);
    mEmail = (TextInputEditText)findViewById(R.id.reg_email);
    mPassword = (TextInputEditText)findViewById(R.id.reg_password);
    mCreateBtn = (Button) findViewById(R.id.reg_create_btn);

    mCreateBtn.setOnClickListener(new View.OnClickListener() {
        @Override
        public void onClick(View view) {
            String displayName = mDisplayName.getEditText().getText().toString();
            String email = mEmail.getEditText().getText().toString();
            String password = mPassword.getEditText().getText().toString();

            registerUser(displayName,email,password);

        }


    });
}

private void registerUser(String displayName, String email, String password) {

   mAuth.signInWithEmailAndPassword(email,password)
           .addOnCompleteListener(this, new OnCompleteListener<AuthResult>() {
               @Override
               public void onComplete(@NonNull Task<AuthResult> task) {
                     if(task.isSuccessful()){
                         Intent mainIntent = new Intent(RegisterActivity.this,MainActivity.class);
                         startActivity(mainIntent);
                         finish();
                     }else{
                         Toast.makeText(RegisterActivity.this,"You got some error.",Toast.LENGTH_SHORT).show();
                     }
               }
           });

}


}

- Cao Minh Vu

Answer 3

你正在尝试在Java文件中将TextInputEditText ID与TextInputLayout类绑定。确保将ID与相同类型的小部件和类名称绑定。

在Java文件中，使用TextInputEditText声明变量而不是TextInputLayout。

private TextInputEditText mDisplayName;
private TextInputEditText mEmail; 
private TextInputEditText mPassword;

在转换时，将TextInputLayout转换为TextInputEditText

mDisplayName = (TextInputEditText)findViewById(R.id.reg_display_name);
mEmail = (TextInputEditText)findViewById(R.id.reg_email);
mPassword = (TextInputEditText)findViewById(R.id.reg_password);

- Karthik

Answer 4

为TextInputEditText创建另一个id，将其用于您的引用

<com.google.android.material.textfield.TextInputLayout
  style="@style/Widget.MaterialComponents.TextInputLayout.OutlinedBox"
        android:id="@+id/textEmail"
        android:layout_width="match_parent"
        android:layout_height="wrap_content"
        android:layout_marginTop="100dp"
        app:boxStrokeColor="@color/purple_700"
        app:boxCornerRadiusTopEnd="100dp"
        app:boxCornerRadiusBottomStart="100dp"
        app:boxCornerRadiusBottomEnd="100dp"
        app:boxCornerRadiusTopStart="100dp"
        app:layout_constraintEnd_toEndOf="parent"
        app:layout_constraintStart_toStartOf="parent"
        app:layout_constraintTop_toTopOf="parent">
        <com.google.android.material.textfield.TextInputEditText
            android:id="@+id/textEditEmail"
            android:layout_width="match_parent"
            android:layout_height="wrap_content"
            android:hint="@string/email" />
</com.google.android.material.textfield.TextInputLayout>
TextInputEditText textEmail = (TextInputEditText)findViewById(R.id.textEditEmail);

- Josh Lea Acquah

Answer 5

从textInputEditText中剪切ID并粘贴到TextInputLayout中。

<com.google.android.material.textfield.TextInputLayout
        android:layout_width="match_parent"
        android:layout_height="wrap_content"
        style="@style/Widget.MaterialComponents.TextInputLayout.OutlinedBox"
        android:hint="Username"
        android:textColorHint="@color/black"
        app:boxStrokeColor="@color/black"
        app:boxStrokeWidthFocused="2dp"
        app:endIconTint="@color/black"
        app:hintTextColor="@color/black"
        app:endIconMode="clear_text"
        app:startIconTint="@color/black"
        android:id="@+id/signup_username_editText"
        >

        <com.google.android.material.textfield.TextInputEditText
           
            android:layout_width="match_parent"
            android:layout_height="match_parent"
            android:inputType="text"
            android:textColor="@color/black"
            android:textCursorDrawable="@null" />
    </com.google.android.material.textfield.TextInputLayout>

- Awais Qarni

Answer 6

我把所有TextInputLayout的ID都改了之后，问题得到了解决。

- Zerman Isakov

Answer 7

我采用了相同的方法，更改了所有字段的ID，问题得到了解决。

- Babar Ali

---

你的回答与之前的重复了。 - Jozott