我有一个matlab程序，但我想将其转换为python，我的matlab代码如下：
function [f]=equation1(x)
%options = optimoptions('fsolve','TolFun',1.1e-20,'TolX',1.1e-20,'maxIter',Inf,'MaxFunEvals',Inf);
c = 330 ;%speed of sound meters per second
% unknown variable :
% r1 => x(1)
% theta => x(2)
time2 = 0.455; % Microphone 1 to Microphone 2 time delay
time3 = 0.606; % Microphone 1 to Microphone 3 time delay
% gives :
r2 = 150 %time2*c;
r3 = 200 %time3*c;
r4 = 499.1; % Distance from Microphone 2 to Microphone 3
r5 = 1267.9;% Distance from Microphone 1 to Microphone 3
phi = 16.177; % Angle between Microphone 1 and Microphone 2 measured from Microphone 3
%
f(1)= (x(1) + r2)^2- (x(1)+r3)^2 -r4^2 +2*(x(1)+r3)*r4*cosd(x(2));
f(2)= x(1)^2 - (x(1)+r3)^2 - r5^2 + 2*(x(1)+r3)*r5*cosd(x(2)-phi);
我使用 [x,feval]=fsolve(@equation1,[100 10]) 运行这段代码，它返回了良好的数值 (1620.7 076.4)。但是在Python中，我需要编写以下程序：
from scipy.optimize import fsolve
import math
def cosd(x):
return math.cos(x * math.pi / 180);
def equations(p):
time2 = 0.455 # Microphone 1 to Microphone 2 time delay
time3 = 0.606 # Microphone 1 to Microphone 3 time delay
# gives :
r2 = 150. #time2*c;
r3 = 200. #time3*c;
r4 = 499.1 # Distance from Microphone 2 to Microphone 3
r5 = 1267.9 # Distance from Microphone 1 to Microphone 3
phi = 16.177 # Angle between Microphone 1 and Microphone 2 measured from Microphone 3
r1, theta = p
f1 = (r1 + r2)**2. -(r1+r3)**2 -r4**2 +2*(r1+r3)*r4*(cosd(theta))
f2 = r1**2 - (r1+r3)**2 - r5**2 + 2*(theta+r3)*r5*(cosd(theta-phi))
return (f1,f2)
x, y = fsolve(equations, (1000.0, 20.0), xtol=1e-06, maxfev=10000000)
print x,y, equations((x, y))
但是当我运行时，遇到了这个错误：
由于上一次的五次雅可比评估没有得到改善，迭代没有取得良好的进展。
warnings.warn(msg, RuntimeWarning)
(-167792.68841940007, -1096453.7938717711)
有人能说说为什么在Python上不起作用吗？
编辑 => 我更改了问题度数的Python代码。 但是我没有得到正确的值（Python返回-4263.77780373 -272.257364385，与Matlab值相差很远）。