我有一个定义好的CLLocation对象,想要将该点向东移动x米并向南移动y米,如何实现?
我有一个定义好的CLLocation对象,想要将该点向东移动x米并向南移动y米,如何实现?
func locationWithBearing(bearingRadians:Double, distanceMeters:Double, origin:CLLocationCoordinate2D) -> CLLocationCoordinate2D { let distRadians = distanceMeters / (6372797.6) // earth radius in meters let lat1 = origin.latitude * M_PI / 180 let lon1 = origin.longitude * M_PI / 180 let lat2 = asin(sin(lat1) * cos(distRadians) + cos(lat1) * sin(distRadians) * cos(bearingRadians)) let lon2 = lon1 + atan2(sin(bearingRadians) * sin(distRadians) * cos(lat1), cos(distRadians) - sin(lat1) * sin(lat2)) return CLLocationCoordinate2D(latitude: lat2 * 180 / M_PI, longitude: lon2 * 180 / M_PI) }
Morgan Chen写道:
该方法中的所有数学计算都是用弧度完成的。在此目的下,lon1和lat1在方法开始时也被转换为弧度。方位角也是以弧度表示的。请记住,该方法考虑了地球的曲率,但对于小距离您不必这样做。
我的评论(2021年3月25日):
在C.F.F. Karney的文章“测地线算法”(2012年)中讨论了在该方法中使用的计算称为求解“直接测地问题”的技术。上面给出的代码使用的技术比Karney文章中介绍的算法要不精确一些。
对Peter答案进行了改进的swift解决方案。唯一的更正是计算时应该使用弧度而不是角度。
func locationWithBearing(bearing:Double, distanceMeters:Double, origin:CLLocationCoordinate2D) -> CLLocationCoordinate2D {
let distRadians = distanceMeters / (6372797.6)
var rbearing = bearing * M_PI / 180.0
let lat1 = origin.latitude * M_PI / 180
let lon1 = origin.longitude * M_PI / 180
let lat2 = asin(sin(lat1) * cos(distRadians) + cos(lat1) * sin(distRadians) * cos(rbearing))
let lon2 = lon1 + atan2(sin(rbearing) * sin(distRadians) * cos(lat1), cos(distRadians) - sin(lat1) * sin(lat2))
return CLLocationCoordinate2D(latitude: lat2 * 180 / M_PI, longitude: lon2 * 180 / M_PI)
}
很棒的帖子,这里是给那些喜欢复制粘贴的人的Obj-C封装:
- (CLLocationCoordinate2D) locationWithBearing:(float)bearing distance:(float)distanceMeters fromLocation:(CLLocationCoordinate2D)origin {
CLLocationCoordinate2D target;
const double distRadians = distanceMeters / (6372797.6); // earth radius in meters
float lat1 = origin.latitude * M_PI / 180;
float lon1 = origin.longitude * M_PI / 180;
float lat2 = asin( sin(lat1) * cos(distRadians) + cos(lat1) * sin(distRadians) * cos(bearing));
float lon2 = lon1 + atan2( sin(bearing) * sin(distRadians) * cos(lat1),
cos(distRadians) - sin(lat1) * sin(lat2) );
target.latitude = lat2 * 180 / M_PI;
target.longitude = lon2 * 180 / M_PI; // no need to normalize a heading in degrees to be within -179.999999° to 180.00000°
return target;
}
有一个 C 函数与你的需求接近,但它需要方位角和距离。可以在我的 github 的 UtilitiesGeo 类中找到该函数。你可以将 CLLocation 中的纬度和经度传递给它,然后从返回的 lat2 和 lon2 创建新的 CLLocation:
/*-------------------------------------------------------------------------
* Given a starting lat/lon point on earth, distance (in meters)
* and bearing, calculates destination coordinates lat2/lon2.
*
* all params in degrees
*-------------------------------------------------------------------------*/
void destCoordsInDegrees(double lat1, double lon1,
double distanceMeters, double bearing,
double* lat2, double* lon2);
奇怪的是,没人想到使用 MapKit 中的 MKCoordinateRegion 来自动计算。
import MapKit
extension CLLocation {
func movedBy(latitudinalMeters: CLLocationDistance, longitudinalMeters: CLLocationDistance) -> CLLocation {
let region = MKCoordinateRegion(center: coordinate, latitudinalMeters: abs(latitudinalMeters), longitudinalMeters: abs(longitudinalMeters))
let latitudeDelta = region.span.latitudeDelta
let longitudeDelta = region.span.longitudeDelta
let latitudialSign = CLLocationDistance(latitudinalMeters.sign == .minus ? -1 : 1)
let longitudialSign = CLLocationDistance(longitudinalMeters.sign == .minus ? -1 : 1)
let newLatitude = coordinate.latitude + latitudialSign * latitudeDelta
let newLongitude = coordinate.longitude + longitudialSign * longitudeDelta
let newCoordinate = CLLocationCoordinate2D(latitude: newLatitude, longitude: newLongitude)
let newLocation = CLLocation(coordinate: newCoordinate, altitude: altitude, horizontalAccuracy: horizontalAccuracy, verticalAccuracy: verticalAccuracy, course: course, speed: speed, timestamp: Date())
return newLocation
}
}
#import <CoreLocation/CoreLocation.h>
@interface CLLocation (Movement)
- (CLLocation *)locationByMovingDistance:(double)distanceMeters withBearing:(CLLocationDirection)bearingDegrees;
@end
@implementation CLLocation (Movement)
- (CLLocation *)locationByMovingDistance:(double)distanceMeters withBearing:(CLLocationDirection)bearingDegrees
{
const double distanceRadians = distanceMeters / (6372797.6); // earth radius in meters
const double bearingRadians = bearingDegrees * M_PI / 180;
float lat1 = self.coordinate.latitude * M_PI / 180;
float lon1 = self.coordinate.longitude * M_PI / 180;
float lat2 = asin(sin(lat1) * cos(distanceRadians) + cos(lat1) * sin(distanceRadians) * cos(bearingRadians));
float lon2 = lon1 + atan2(sin(bearingRadians) * sin(distanceRadians) * cos(lat1),
cos(distanceRadians) - sin(lat1) * sin(lat2) );
return [[CLLocation alloc] initWithLatitude:lat2 * 180 / M_PI
longitude:lon2 * 180 / M_PI];
}
@end
更简单的解决方案是使用MKMapPoints。
使用以下方法将您的原始坐标和任何偏移距离转换为MKMapPoints:
let coordinatesInMapPoints = MKMapPointForCoordinate(CLLocationCoordinate2D)
let distancesInMapPoints = yourDistanceInMeters * MKMapPointsPerMeterAtLatitude(CLLocationDegrees) // Do this for both x and y directions if needed.
然后,通过将偏移距离加到原始坐标上,简单地创建一个新的MKMapPoint:
let newCoordinatesInMapPoints = MKMapPointMake(coordinatesInMapPoints.x + distancesInMapPoints, coordinatesInMapPoints.y)
let newCoordinate = MKCoordinateForMapPoint(newCoordinatesInMapPoints)
使用Measurement
结构实现Swift代码,用于在度和弧度之间进行转换。
class GPSLocation {
public class func degreesToRadians(degrees: Double) -> Double {
return Measurement(value: degrees, unit: UnitAngle.degrees).converted(to: .radians).value
}
public class func radiansToDegrees(radians: Double) -> Double {
return Measurement(value: radians, unit: UnitAngle.radians).converted(to: .degrees).value
}
public class func location(location: CLLocation, byMovingDistance distance: Double, withBearing bearingDegrees:CLLocationDirection) -> CLLocation {
let distanceRadians: Double = distance / 6372797.6
let bearingRadians: Double = GPSLocation.degreesToRadians(degrees: bearingDegrees)
let lat1 = GPSLocation.degreesToRadians(degrees: location.coordinate.latitude)
let lon1 = GPSLocation.degreesToRadians(degrees: location.coordinate.longitude)
let lat2 = GPSLocation.radiansToDegrees(radians:asin(sin(lat1) * cos(distanceRadians) + cos(lat1) * sin(distanceRadians) * cos(bearingRadians)))
let lon2 = GPSLocation.radiansToDegrees(radians:lon1 + atan2(sin(bearingRadians) * sin(distanceRadians * cos(lat1)), cos(distanceRadians) - sin(lat1) * sin(lat2)))
return CLLocation(latitude: lat2, longitude: lon2)
}
}
Swift 4
extension CLLocationCoordinate2D {
/// Get coordinate moved from current to `distanceMeters` meters with azimuth `azimuth` [0, Double.pi)
///
/// - Parameters:
/// - distanceMeters: the distance in meters
/// - azimuth: the azimuth (bearing)
/// - Returns: new coordinate
func shift(byDistance distanceMeters: Double, azimuth: Double) -> CLLocationCoordinate2D {
let bearing = azimuth
let origin = self
let distRadians = distanceMeters / (6372797.6) // earth radius in meters
let lat1 = origin.latitude * Double.pi / 180
let lon1 = origin.longitude * Double.pi / 180
let lat2 = asin(sin(lat1) * cos(distRadians) + cos(lat1) * sin(distRadians) * cos(bearing))
let lon2 = lon1 + atan2(sin(bearing) * sin(distRadians) * cos(lat1), cos(distRadians) - sin(lat1) * sin(lat2))
return CLLocationCoordinate2D(latitude: lat2 * 180 / Double.pi, longitude: lon2 * 180 / Double.pi)
}
}
let point: CLLocationCoordinate2D!
let north100 = point.shift(byDistance: 100, azimuth: 0) // 100m to North
let south100 = point.shift(byDistance: 100, azimuth: Double.pi) // 100m to South
作为CGPoint扩展的Swift 4.2
源自Peter O.的解决方案
FloatingPoint扩展:感谢https://dev59.com/X14b5IYBdhLWcg3waA5P#29179878
extension FloatingPoint
{
var degreesToRadians: Self { return self * .pi / 180 }
var radiansToDegrees: Self { return self * 180 / .pi }
}
extension CGPoint
{
// NOTE: bearing is in radians
func locationWithBearing(bearing: Double, distanceMeters: Double) -> CGPoint
{
let distRadians = distanceMeters / (6372797.6) // earth radius in meters
let origLat = Double(self.y.degreesToRadians)
let origLon = Double(self.x.degreesToRadians)
let newLat = asin(sin(origLat) * cos(distRadians) + cos(origLat) * sin(distRadians) * cos(bearing))
let newLon = origLon + atan2(sin(bearing) * sin(distRadians) * cos(origLat), cos(distRadians) - sin(origLat) * sin(newLat))
return CGPoint(x: newLon.radiansToDegrees, y: newLat.radiansToDegrees)
}
}
使用方法:
let loc = CGPoint(x: lon, y: lat)
let newLoc = loc.locationWithBearing(bearing: 90.degreesToRadians, distanceMeters: 500.0)