通常认为在 PowerShell 中做不到这点。经过几次谷歌搜索和在 Stack Overflow 上的搜索后,我差点放弃。但是后来我发现了这篇关于gist的文章,结果证明你是可以做到的!
鉴于这对我来说很难发现,我想为其他人提供一个清晰和格式良好的示例(以及当我忘记如何做到这一点时,也方便我的未来自己)
感谢JFFail将此代码发布到 Github
您需要根据需要重载它们,它们应该是不言自明的,但如果有什么不清楚的地方,请随时问
SetValue([int]$newValue)
GetValue()
[boolean] Equals($otherNumber)
[string] ToString()
static [MyClass] op_Addition ([MyClass]$first, [MyClass]$second)
static [MyClass] op_Subtraction([MyClass]$first, [MyClass]$second)
static [MyClass] op_Multiply ([MyClass]$first, [MyClass]$second)
static [MyClass] op_Division ([MyClass]$first, [MyClass]$second)
对于 -gt
和 -lt
,您需要使用以下代码。请注意,虽然这支持 -eq
,但是您可以通过上面所示的 Equals(object)
单独获得它,并且不需要从 IComparable
继承。
class MyClass : System.IComparable
[int] CompareTo($otherNumber)
以下是一个可用的示例
class Number : System.IComparable
{
[int] $value = 0
Number() {}
Number ([int]$somethingElse)
{$this.value = $somethingElse}
[void] SetValue ([int]$newValue)
{$this.value = $newValue}
[int] GetValue()
{return $this.value}
[boolean] Equals($otherNumber)
{
if ($this.value -eq $otherNumber.GetValue())
{return $true}
else
{return $false}
}
[int] CompareTo($otherNumber)
{
if ($this.value -gt $otherNumber.GetValue()) {return 1}
if ($this.value -eq $otherNumber.GetValue()) {return 0}
if ($this.value -lt $otherNumber.GetValue()) {return -1}
return $null
}
[string] ToString()
{return $this.value.ToString()}
static [Number] op_Addition ([Number]$first, [Number]$second)
{return [Number]::new($first.GetValue() + $second.GetValue())}
static [Number] op_Subtraction([Number]$first, [Number]$second)
{return [Number]::new($first.GetValue() - $second.GetValue())}
static [Number] op_Multiply([Number]$first, [Number]$second)
{return [Number]::new($first.GetValue() * $second.GetValue())}
static [Number] op_Division([Number]$first, [Number]$second)
{return [Number]::new($first.GetValue() / $second.GetValue())}
}
$firstNumber = [Number]::new(8)
$secondNumber = [Number]::new(12)
$thirdNumber = [Number]::new(8)
if ($firstNumber -eq $secondNumber)
{Write-Output ("{0} == {1}" -F $firstNumber, $secondNumber)}
else
{Write-Output ("{0} <> {1}" -F $firstNumber, $secondNumber)}
if ($firstNumber -eq $thirdNumber)
{Write-Output ("{0} == {1}" -F $firstNumber, $thirdNumber)}
else
{Write-Output ("{0} <> {1}" -F $firstNumber, $thirdNumber)}
switch ($true)
{
($firstNumber -gt $secondNumber) {Write-Output ("{0} > {1}" -F $firstNumber, $secondNumber)}
($firstNumber -eq $secondNumber) {Write-Output ("{0} == {1}" -F $firstNumber, $secondNumber)}
($firstNumber -lt $secondNumber) {Write-Output ("{0} < {1}" -F $firstNumber, $secondNumber)}
}
$fourthNumber = $firstNumber + $secondNumber
Write-Output ("{0} = {1} + {2}" -F $fourthNumber, $firstNumber, $secondNumber)
$fifthNumber = $secondNumber - $thirdNumber
Write-Output ("{0} = {1} - {2}" -F $fifthNumber, $secondNumber, $thirdNumber)
$sixthNumber = $firstNumber * $secondNumber
Write-Output ("{0} = {1} * {2}" -F $sixthNumber, $firstNumber, $secondNumber)
$seventhNumber = $sixthNumber / $firstNumber
Write-Output ("{0} = {1} / {2}" -F $seventhNumber, $sixthNumber, $firstNumber)
以下是输出结果
> 8 <> 12
> 8 == 8
> 8 < 12
> 20 = 8 + 12
> 4 = 12 - 8
> 96 = 8 * 12
> 12 = 96 / 8