如果我想创建类似于AT&T下拉菜单上看到的分隔菜单项的渐变线,如何实现呢?我想在我编写的菜单上创建类似的效果,并且我不想使用图像。是否有一种方法可以在CSS中实现这一点?非常感谢您的帮助!谢谢。
Microsoft CSS Gradient 是一个可视化工具,你可以使用它。只需要将CSS复制到你的代码中:
例如:
#div {
/* IE10 Consumer Preview */
background-image: -ms-linear-gradient(bottom, #FFFFFF 0%, #00A3EF 100%);
/* Mozilla Firefox */
background-image: -moz-linear-gradient(bottom, #FFFFFF 0%, #00A3EF 100%);
/* Opera */
background-image: -o-linear-gradient(bottom, #FFFFFF 0%, #00A3EF 100%);
/* Webkit (Safari/Chrome 10) */
background-image: -webkit-gradient(linear, left bottom, left top, color-stop(0, #FFFFFF), color-stop(1, #00A3EF));
/* Webkit (Chrome 11+) */
background-image: -webkit-linear-gradient(bottom, #FFFFFF 0%, #00A3EF 100%);
/* W3C Markup, IE10 Release Preview */
background-image: linear-gradient(to top, #FFFFFF 0%, #00A3EF 100%);
}
.line{
width:1px;
height : 25px;
margin : 0 5px;
background: rgb(125,185,232);
background: url(data:image/svg+xml;base64,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);
background: -moz-linear-gradient(top, rgba(125,185,232,1) 0%, rgba(30,87,153,1) 50%, rgba(125,185,232,1) 100%);
background: -webkit-gradient(linear, left top, left bottom, color-stop(0%,rgba(125,185,232,1)), color-stop(50%,rgba(30,87,153,1)), color-stop(100%,rgba(125,185,232,1)));
background: -webkit-linear-gradient(top, rgba(125,185,232,1) 0%,rgba(30,87,153,1) 50%,rgba(125,185,232,1) 100%);
background: -o-linear-gradient(top, rgba(125,185,232,1) 0%,rgba(30,87,153,1) 50%,rgba(125,185,232,1) 100%);
background: -ms-linear-gradient(top, rgba(125,185,232,1) 0%,rgba(30,87,153,1) 50%,rgba(125,185,232,1) 100%);
background: linear-gradient(to bottom, rgba(125,185,232,1) 0%,rgba(30,87,153,1) 50%,rgba(125,185,232,1) 100%);
filter: progid:DXImageTransform.Microsoft.gradient( startColorstr='#7db9e8', endColorstr='#7db9e8',GradientType=0 );
}
Fiddle: http://jsfiddle.net/jPnXz/
这里有一个CSS渐变生成器(我用它来制作CSS):http://www.colorzilla.com/gradient-editor/
对于这个问题,您也可以使用repeating-gradient:
http://codepen.io/anon/pen/zbLkl
background:repeating-linear-gradient(
top ,
white 0,
white 1em,
turquoise 1em,
turquoise 1.2em) 0 2.4em;
line-height:1.2em;
background:
linear-gradient(0deg, rgba(0,0,0,0.1) 0 , rgba(0,0,0,0.1) 1px ,transparent 1px ,transparent),
linear-gradient(90deg, rgba(0,0,0,0.1) 0 , rgba(0,0,0,0.1) 1px ,transparent 1px ,transparent);
background-size:1.4em 1.4em,1.4em 1.4em;
line-height:1.4em;
<!DOCTYPE html>
<html>
<head>
<style>
#grad1 {
height: 200px;
background: linear-gradient(to top left ,#FFA500, #DDA0DD,#FFFAF0,#bfff00,#00ffff,#A9A9A9);
}
</style>
</head>
<body>
<h1>Linear Gradient</h1>
<div id="grad1"></div>
<br/>
<div>Internet Explorer 9 and earlier versions do not support gradients</div>
</body>
</html>