我希望能够通过拖动来移动PopupWindow。我不希望UI在释放触摸时更新,我希望PopupWindow跟随我的触摸移动。
这是我正在做的事情:
mView = mLayoutInflater.inflate(R.layout.popup,
null);
mPopupWindow = new PopupWindow(mView,
LayoutParams.WRAP_CONTENT, LayoutParams.WRAP_CONTENT, false);
mPopupWindow.showAtLocation(parentView, Gravity.CENTER, -5, 30);
mView.setOnTouchListener(new OnTouchListener() {
private int dx = 0;
private int dy = 0;
@Override
public boolean onTouch(View view, MotionEvent motionEvent) {
switch (motionEvent.getAction()) {
case MotionEvent.ACTION_DOWN:
dx = (int) motionEvent.getX();
dy = (int) motionEvent.getY();
break;
case MotionEvent.ACTION_MOVE:
int x = (int) motionEvent.getX();
int y = (int) motionEvent.getY();
int left = (x - dx);
int top = (y - dy);
Log.d("test", "x: " + left + " y: " + top);
mPopupWindow.update(left, top, -1, -1);
break;
}
return true;
}
});
当我拖动弹出窗口时,它会在原始位置和我的手指所在的位置之间闪烁。
闪烁的Logcat结果:
x: -44 y: 4
x: -43 y: 37
x: -46 y: 4
x: -46 y: 38
x: -48 y: 4
x: -47 y: 38
x: -50 y: 4
但是如果我注释掉 "mPopupWindow.update(left, top, -1, -1);",它会返回正确的结果。(但显然UI不会更新):
x: -33 y: 0
x: -37 y: 0
x: -41 y: 0
x: -43 y: 3
x: -46 y: 3
x: -50 y: 3
x: -54 y: 4
x: -57 y: 4
我该如何正确移动PopupWindow?