我需要创建一个实时报告。为此,我必须为给定日期的每个小时编写条件。在下面的代码中,条件检查当前星期几,然后检查当前时间,并根据此生成报告。
protected void sample()
{
TimeSpan zerothHour = new TimeSpan(00, 0, 0);
TimeSpan firstHour = new TimeSpan(01, 0, 0);
TimeSpan secondHour = new TimeSpan(02, 0, 0);
TimeSpan thirdHour = new TimeSpan(03, 0, 0);
TimeSpan fourthHour = new TimeSpan(04, 0, 0);
TimeSpan fifthHour = new TimeSpan(05, 0, 0);
TimeSpan sixthHour = new TimeSpan(06, 0, 0);
// and so on until the twentyfourth hour
if (DateTime.Today.DayOfWeek == DayOfWeek.Monday)
{
if (DateTime.Now.TimeOfDay >= sixthHour && DateTime.Now.TimeOfDay <= seventhHour)
{
//MySql query here
string MyConString = ConfigurationManager.ConnectionStrings["connStr"].ConnectionString;
MySqlConnection connection = new MySqlConnection(MyConString);
string agentlogin = "SELECT agentlogin FROM agentdetails WHERE location = 'PNQ10-Pune' AND shift IN('6:00-15-00', '22:00-7:00') AND Mon = 'W'";
MySqlCommand cmd = new MySqlCommand(agentlogin, connection);
connection.Open();
MySqlDataReader rdr = cmd.ExecuteReader();
while (rdr.Read())
{
//lblagentlogin.Text += rdr["agentlogin"] + Environment.NewLine;
sqlList.Add(Convert.ToString(rdr["agentlogin"]));
}
}
else if(DateTime.Now.TimeOfDay >= seventhHour && DateTime.Now.TimeOfDay <= eigthHour)
{
}
else if (DateTime.Now.TimeOfDay >= eigthHour && DateTime.Now.TimeOfDay <= ninthHour)
{
}
else if (DateTime.Now.TimeOfDay >= ninthHour && DateTime.Now.TimeOfDay <= tenthHour)
{
}
else if (DateTime.Now.TimeOfDay >= tenthHour && DateTime.Now.TimeOfDay <= eleventhHour)
{
}
// and so on for the entire cycle of time
}
}
上面的代码仅适用于星期一,我还需要为其他七天做同样的事情。如果我在每个条件中添加查询,代码将变成数百行。
有没有更好的方法,在不必编写数百行代码的情况下完成此操作?
for
循环怎么样?或者使用Quartz进行任务调度呢? - ProgrammingLlamaDateTime.Today.TimeOfDay <= seventhHour
,你应该使用<
而不是<=
。 - Hans Kesting