如何使用Entity Framework简化if else语句

3

如何简化下面的代码:

public List<Cwzz_CashFlowItem> AllDataPage(int start, int limit, out int total, string xmbmLike, string xmmcLike)
{
    List<Cwzz_CashFlowItem> ll;
    if (xmbmLike != "" && xmmcLike != "")
    {
        total = _ctx.Cwzz_CashFlowItem
                    .Where(v => v.CashFlowCode.Contains(xmbmLike))
                    .Count(v => v.CashFlowName.Contains(xmmcLike));

        ll = _ctx.Cwzz_CashFlowItem
                 .Where(v => v.CashFlowCode.Contains(xmbmLike))
                 .Where(v => v.CashFlowName.Contains(xmmcLike))
                 .OrderBy(v => v.CashFlowCode).Skip(start).Take(limit).ToList();
    }
    else if (xmbmLike != "" && xmmcLike == "")
    {
        total = _ctx.Cwzz_CashFlowItem
                    .Count(v => v.CashFlowCode.Contains(xmbmLike));

        ll = _ctx.Cwzz_CashFlowItem
                 .Where(v => v.CashFlowCode.Contains(xmbmLike))
                 .OrderBy(v => v.CashFlowCode).Skip(start).Take(limit).ToList();
    }
    else if (xmbmLike == "" && xmmcLike != "")
    {
        total = _ctx.Cwzz_CashFlowItem
                    .Count(v => v.CashFlowName.Contains(xmmcLike));

        ll = _ctx.Cwzz_CashFlowItem
                 .Where(v => v.CashFlowName.Contains(xmmcLike))
                 .OrderBy(v => v.CashFlowCode).Skip(start).Take(limit).ToList();
    }
    else
    {
        total = _ctx.Cwzz_CashFlowItem.Count();

        ll = _ctx.Cwzz_CashFlowItem
                 .OrderBy(v => v.CashFlowCode)
                 .Skip(start).Take(limit).ToList();
    }
    return ll;
}

如果有多个条件而不是两个,if-else语句会变得更加复杂。那么如何简化上述代码呢?
1个回答

3
Linq表达式可以链式调用。避免过早地将其强制转换为List<>。
 public IQueryable<Cwzz_CashFlowItem> AllDataPage(...) {
    IQueryable<Cwzz_CashFlowItem> ll =  _ctx.Cwzz_CashFlowItem;

    if (xmbmLike != "")
    {
      ll = ll.Where(v => v.CashFlowCode.Contains(xmbmLike));
    }

    if (xmcmLike != "")
    {
      ll = ll.Where(v => v.CashFlowCode.Contains(xmcmLike));
    }

    return ll.OrderBy(v => v.CashFlowCode).Skip(start).Take(limit);
   }

我将把返回 out Count 的任务留作练习。


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