语法看起来就像从MDN上复制粘贴过来的,所以我不明白为什么这个解构对象不起作用。变量返回未定义,为什么?
let obj={age: "3", name: "spike"};
let {a,b}=obj;//returns a and b as undefined, why?
let obj={age: "3", name: "spike"};
let {a,b}=obj;//returns a and b as undefined, why?
name
和age
作为从对象解构出来的变量,如下所示:
let obj={age: "3", name: "spike"};
let {age, name}=obj;
console.log(age);
console.log(name);
或者,您可以使用以下语法为解构变量分配新名称:
let obj={age: "3", name: "spike"};
let {age: a, name: b}=obj;
console.log(a);
console.log(b);
let obj={age: "3", name: "spike"};
let {age:a, name:b}=obj;
console.log(a); //prints "3"
console.log(b); //prints "spike"
你需要传递与对象中相同的变量名,而在你的情况下它将是
let obj={age: "3", name: "spike"};
let {age,name}=obj;