这有可能吗?
#include <array>
#include <initializer_list>
struct A
{
A ( std::initializer_list< int > l )
: m_a ( l )
{
}
std::array<int,2> m_a;
};
int main()
{
A a{ 1,2 };
}
但是这会导致出现以下错误:
t.cpp: In constructor ‘A::A(std::initializer_list<int>)’:
t.cpp:7:19: error: no matching function for call to ‘std::array<int, 2ul>::array(std::initializer_list<int>&)’
: m_a ( l )
^
t.cpp:7:19: note: candidates are:
In file included from t.cpp:1:0:
/usr/lib/gcc/x86_64-pc-linux-gnu/4.8.2/include/g++-v4/array:81:12: note: std::array<int, 2ul>::array()
struct array
^
/usr/lib/gcc/x86_64-pc-linux-gnu/4.8.2/include/g++-v4/array:81:12: note: candidate expects 0 arguments, 1 provided
/usr/lib/gcc/x86_64-pc-linux-gnu/4.8.2/include/g++-v4/array:81:12: note: constexpr std::array<int, 2ul>::array(const std::array<int, 2ul>&)
/usr/lib/gcc/x86_64-pc-linux-gnu/4.8.2/include/g++-v4/array:81:12: note: no known conversion for argument 1 from ‘std::initializer_list<int>’ to ‘const std::array<int, 2ul>&’
/usr/lib/gcc/x86_64-pc-linux-gnu/4.8.2/include/g++-v4/array:81:12: note: constexpr std::array<int, 2ul>::array(std::array<int, 2ul>&&)
/usr/lib/gcc/x86_64-pc-linux-gnu/4.8.2/include/g++-v4/array:81:12: note: no known conversion for argument 1 from ‘std::initializer_list<int>’ to ‘std::array<int, 2ul>&&’
initializer_list
的元素:A (std::initializer_list<int> l) /*不要初始化m_a*/ { std::copy(l.begin(),l.end(),m_a.begin());}
- Mankarsestd::initializer_list<int> x = { 1, 2 }; std::array<int, 2> m { ?????? };
中也会出现相同的问题。您只能在此处放置作为聚合初始化的一部分的内容,即每个元素的初始化程序一个接一个地进行。 - M.M