我正在使用Express构建一个Web应用程序。我想合并、压缩和提供.js文件。我编写了一个中间件,这是我的代码:
var fs = require('fs'),
path = require('path'),
uglify = require('uglify-js'),
cache = '',
scriptsDir = path.join(__dirname, '../scripts'),
files = fs.readdirSync(scriptsDir);
// Sync read is not a problem since the following code is executed on startup
files.forEach(function(fname) {
if (/^.*\.js$/.test(fname)) {
cache += fs.readFileSync(path.join(scriptsDir, fname), 'utf8').toString();
}
});
cache = uglify.minify(cache, { fromString: true }).code;
module.exports = function(req, res, next) {
if (req.url === '/js/all.js')
res.end(cache);
else
next();
};
中间件使用方法如下:
app.use(compress());
[...]
app.use(app.router);
app.use(jsMerger); // Here is my middleware
app.use(express.static(path.join(__dirname, '../public')));
问题在于响应未压缩。此外,响应中没有“标题”(我的意思是,没有缓存标题、ETag;使用 static
中间件提供的其他资源具有这些标题)。以下是响应内容:
X-Powered-By: Express
Transfer-Encoding: chunked
Date: Wed, 12 Mar 2014 14:04:19 GMT
Connection: keep-alive
我有点不明白,如何压缩响应呢?
uglify = require('uglify-js')
导入了uglify.js2库(https://github.com/mishoo/UglifyJS2)。 - mneri