JavaFX如何更改舞台(stage)？

Question

我正在使用Netbeans 7.2和Scene Builder 1.0来开发JavaFX应用程序。 我已经设置好了主屏幕，并希望点击一个按钮后它会关闭主窗口并打开另一个窗口。 主Stage对象位于主类中，但控制器类是单独的，无法访问它，因为它不是静态的且位于不同的类中。 如何更改场景或舞台？

- Tyler Petrochko

Answer 1

下载JavaFX示例，查找FXML-LoginDemo项目，这就是你需要的。为了方便参考，我在这里复制粘贴了主要的Java类；）

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package demo;

import demo.model.User;
import demo.security.Authenticator;
import java.util.logging.Level;
import java.util.logging.Logger;
import javafx.application.Application;
import javafx.fxml.FXMLLoader;
import javafx.fxml.JavaFXBuilderFactory;
import javafx.scene.Parent;
import javafx.scene.Scene;
import javafx.stage.Stage;

/**
 * Main Application. This class handles navigation and user session.
 */
public class App extends Application {
    private Stage stage;
    private User loggedUser;

    private static App instance;

    public App() {
        instance = this;
    }

    public static App getInstance() {
        return instance;
    }

    /**
     * @param args the command line arguments
     */
    public static void main(String[] args) {
        launch(args);
    }

    @Override public void start(Stage primaryStage) {
        try {
            stage = primaryStage;
            gotoLogin();
            primaryStage.show();
        } catch (Exception ex) {
            Logger.getLogger(App.class.getName()).log(Level.SEVERE, null, ex);
        }
    }

    public User getLoggedUser() {
        return loggedUser;
    }

    public boolean userLogging(String userId, String password){
        if (Authenticator.validate(userId, password)) {
            loggedUser = User.of(userId);
            gotoProfile();
            return true;
        } else {
            return false;
        }
    }

    public void userLogout(){
        loggedUser = null;
        gotoLogin();
    }

    private void gotoProfile() {
        try {
            replaceSceneContent("profile.fxml");
        } catch (Exception ex) {
            Logger.getLogger(App.class.getName()).log(Level.SEVERE, null, ex);
        }
    }

    private void gotoLogin() {
        try {
            replaceSceneContent("login.fxml");
        } catch (Exception ex) {
            Logger.getLogger(App.class.getName()).log(Level.SEVERE, null, ex);
        }
    }

    private Parent replaceSceneContent(String fxml) throws Exception {
        Parent page = (Parent) FXMLLoader.load(App.class.getResource(fxml), null, new JavaFXBuilderFactory());
        Scene scene = stage.getScene();
        if (scene == null) {
            scene = new Scene(page, 700, 450);
            scene.getStylesheets().add(App.class.getResource("demo.css").toExternalForm());
            stage.setScene(scene);
        } else {
            stage.getScene().setRoot(page);
        }
        stage.sizeToScene();
        return page;
    }
}

- invariant

---

现在这样做是正确的吗？我的意思是，我可以在App类之外调用.replaceSceneContent吗？或者说在今天（2015年）有更好的方法来切换场景吗？谢谢=） - user2582318

我该如何在控制器类中使用这个？还是说我只能在主应用程序中使用它？ - Ahmed Hasn.

这个答案已经过时了，今天不再适用 :( - Dan A.S.

Answer 2

我可能会说类似的话，但这是我的做法：

（在这个例子中，我从Login.fxml过渡到Home.fxml）。

在LoginController.fxml类内，我创建了以下方法：

@FXML
private void login(javafx.event.ActionEvent event) throws IOException
{
    if(pwf1.getText().equals("dolphin"))
    {
            Parent blah = FXMLLoader.load(getClass().getResource("Home.fxml"));
            Scene scene = new Scene(blah);
            Stage appStage = (Stage) ((Node) event.getSource()).getScene().getWindow();
            appStage.setScene(scene);
            appStage.show();
    }
    else
    {
            label1.setText("Password is incorrect. Please Try Again");
    }
}

就是这样了。;)

- CodingAddict

Answer 3

你也可以这样做：

按照以下方式修改你的controller.java文件

Stage thisStage;

public void setStage (Stage stage){
    thisStage = stage;
}

public void showStage(){
    thisStage.setTitle("Titel in der MainController.java geändert");
    thisStage.show();
}

重要的是，在initialize方法中不要使用thisStage。

按照以下方式修改您的Mainclass：

@Override
public void start(Stage stage) throws Exception {
    URL location = getClass().getResource("Main.fxml");
    FXMLLoader fxmlLoader = new FXMLLoader();
    fxmlLoader.setLocation(location);
    fxmlLoader.setBuilderFactory(new JavaFXBuilderFactory());
    Parent root = (Parent) fxmlLoader.load(location.openStream());
    Scene scene = new Scene(root);
    stage.setScene(scene);
    MainController mainController = fxmlLoader.getController();
    mainController.setStage(stage);
    mainController.showStage();
}

您可以在此处下载一个示例项目（NetBeans）这里。

- JackTools.Net

---

链接已经失效了，你能给我们提供另一个链接吗？ - Ahmed Hasn.

Answer 4

根据您的问题，最近我正在开发一个iOS等效的NavigationController用于JavaFX，使用最简单的推送和关闭视图的思路。

让我与社区分享代码：https://github.com/jalopezsuarez/javafx-screens 这个想法是为您提供一个非常简单的环境，以帮助您在屏幕之间切换。

希望能对您有所帮助。

- jalopezsuarez