从多个列表生成Python字典

Question

我尝试解决了我的问题，但我无法解决。

我有三个Python列表:

atr = ['a','b','c']
m = ['h','i','j']
func = ['x','y','z']

我的问题是根据这三个列表的组合生成一个Python字典：

期望输出结果：

py_dict = {
    'a': [('x','h'), ('x','i'), ('x','j'), ('y','h'), ('y','i'), ('y','j'),('z','h'), ('z','i'), ('z','j')],
    'b': [('x','h'), ('x','i'), ('x','j'), ('y','h'), ('y','i'), ('y','j'),('z','h'), ('z','i'), ('z','j')],
    'c': [('x','h'), ('x','i'), ('x','j'), ('y','h'), ('y','i'), ('y','j'),('z','h'), ('z','i'), ('z','j')]
}

- user46543

Answer 1

你可以使用 itertools.product：

import itertools
atr = ['a','b','c']
m = ['h','i','j']
func = ['x','y','z']
prod = list(itertools.product(func, m))
result = {i:prod for i in atr}

输出：

{'a': [('x', 'h'), ('x', 'i'), ('x', 'j'), ('y', 'h'), ('y', 'i'), ('y', 'j'), ('z', 'h'), ('z', 'i'), ('z', 'j')], 'b': [('x', 'h'), ('x', 'i'), ('x', 'j'), ('y', 'h'), ('y', 'i'), ('y', 'j'), ('z', 'h'), ('z', 'i'), ('z', 'j')], 'c': [('x', 'h'), ('x', 'i'), ('x', 'j'), ('y', 'h'), ('y', 'i'), ('y', 'j'), ('z', 'h'), ('z', 'i'), ('z', 'j')]}

- Ajax1234

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谢谢兄弟，哦天啊，我才知道Python有这种函数。 - user46543