在Ruby on Rails中，有一种功能可以将任何日期打印出多久以前的时间。例如：
8 minutes ago
8 hours ago
8 days ago
8 months ago
8 years ago
有没有在Java中简单的方法来做到这一点？
如何在Java中计算“时间之前”？
147
- jts
1
1请参考以下链接：https://dev59.com/b3VD5IYBdhLWcg3wXamd
这是C#的代码，但我相信你可以轻松转换它。 - Brandon
33个回答
1
针对Android 正如Ravi所说，但是由于许多人想要复制粘贴这个东西，因此在这里提供。
try {
SimpleDateFormat formatter = new SimpleDateFormat("EEE, dd MMM yyyy HH:mm:ss Z");
Date dt = formatter.parse(date_from_server);
CharSequence output = DateUtils.getRelativeTimeSpanString (dt.getTime());
your_textview.setText(output.toString());
} catch (Exception ex) {
ex.printStackTrace();
your_textview.setText("");
}
有更多时间的人的解释
- 你从某个地方获取数据。首先，你需要弄清楚它的格式。
例如，我从服务器获取的数据格式为 Wed, 27 Jan 2016 09:32:35 GMT [这可能不是你的情况]
这被翻译为
SimpleDateFormat formatter = new SimpleDateFormat("EEE, dd MMM yyyy HH:mm:ss Z");
我怎么知道的？阅读此处的文档。
然后，在我解析它之后，我得到了一个日期。我把那个日期放在 getRelativeTimeSpanString 中（没有任何额外的参数对我来说都可以，默认为分钟）
如果你没有弄清楚正确的解析字符串，你将会得到一个异常，类似于字符5处的异常。 查看第5个字符，并纠正你的初始解析字符串。你可能会遇到另一个异常，请重复这些步骤，直到你有正确的公式。
- OWADVL
1
将SQL时间戳转换为现在的已过时间。设置您自己的时区。
注意1：这将处理单数/复数。
注意2：这是使用Joda时间。
String getElapsedTime(String strMysqlTimestamp) {
DateTimeFormatter formatter = DateTimeFormat.forPattern("YYYY-MM-dd HH:mm:ss.S");
DateTime mysqlDate = formatter.parseDateTime(strMysqlTimestamp).
withZone(DateTimeZone.forID("Asia/Kuala_Lumpur"));
DateTime now = new DateTime();
Period period = new Period(mysqlDate, now);
int seconds = period.getSeconds();
int minutes = period.getMinutes();
int hours = period.getHours();
int days = period.getDays();
int weeks = period.getWeeks();
int months = period.getMonths();
int years = period.getYears();
String elapsedTime = "";
if (years != 0)
if (years == 1)
elapsedTime = years + " year ago";
else
elapsedTime = years + " years ago";
else if (months != 0)
if (months == 1)
elapsedTime = months + " month ago";
else
elapsedTime = months + " months ago";
else if (weeks != 0)
if (weeks == 1)
elapsedTime = weeks + " week ago";
else
elapsedTime = weeks + " weeks ago";
else if (days != 0)
if (days == 1)
elapsedTime = days + " day ago";
else
elapsedTime = days + " days ago";
else if (hours != 0)
if (hours == 1)
elapsedTime = hours + " hour ago";
else
elapsedTime = hours + " hours ago";
else if (minutes != 0)
if (minutes == 1)
elapsedTime = minutes + " minute ago";
else
elapsedTime = minutes + " minutes ago";
else if (seconds != 0)
if (seconds == 1)
elapsedTime = seconds + " second ago";
else
elapsedTime = seconds + " seconds ago";
return elapsedTime;
}
- jumper rbk
1
经过长时间的研究，我找到了这个。
public class GetTimeLapse {
public static String getlongtoago(long createdAt) {
DateFormat userDateFormat = new SimpleDateFormat("E MMM dd HH:mm:ss Z yyyy");
DateFormat dateFormatNeeded = new SimpleDateFormat("MM/dd/yyyy HH:MM:SS");
Date date = null;
date = new Date(createdAt);
String crdate1 = dateFormatNeeded.format(date);
// Date Calculation
DateFormat dateFormat = new SimpleDateFormat("MM/dd/yyyy HH:mm:ss");
crdate1 = new SimpleDateFormat("MM/dd/yyyy HH:mm:ss").format(date);
// get current date time with Calendar()
Calendar cal = Calendar.getInstance();
String currenttime = dateFormat.format(cal.getTime());
Date CreatedAt = null;
Date current = null;
try {
CreatedAt = dateFormat.parse(crdate1);
current = dateFormat.parse(currenttime);
} catch (java.text.ParseException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
// Get msec from each, and subtract.
long diff = current.getTime() - CreatedAt.getTime();
long diffSeconds = diff / 1000;
long diffMinutes = diff / (60 * 1000) % 60;
long diffHours = diff / (60 * 60 * 1000) % 24;
long diffDays = diff / (24 * 60 * 60 * 1000);
String time = null;
if (diffDays > 0) {
if (diffDays == 1) {
time = diffDays + "day ago ";
} else {
time = diffDays + "days ago ";
}
} else {
if (diffHours > 0) {
if (diffHours == 1) {
time = diffHours + "hr ago";
} else {
time = diffHours + "hrs ago";
}
} else {
if (diffMinutes > 0) {
if (diffMinutes == 1) {
time = diffMinutes + "min ago";
} else {
time = diffMinutes + "mins ago";
}
} else {
if (diffSeconds > 0) {
time = diffSeconds + "secs ago";
}
}
}
}
return time;
}
}
- Hari krishna Andhra Pradesh
1
你可以使用Java的库RelativeDateTimeFormatter，它恰好可以做到这一点：
RelativeDateTimeFormatter fmt = RelativeDateTimeFormatter.getInstance();
fmt.format(1, Direction.NEXT, RelativeUnit.DAYS); // "in 1 day"
fmt.format(3, Direction.NEXT, RelativeUnit.DAYS); // "in 3 days"
fmt.format(3.2, Direction.LAST, RelativeUnit.YEARS); // "3.2 years ago"
fmt.format(Direction.LAST, AbsoluteUnit.SUNDAY); // "last Sunday"
fmt.format(Direction.THIS, AbsoluteUnit.SUNDAY); // "this Sunday"
fmt.format(Direction.NEXT, AbsoluteUnit.SUNDAY); // "next Sunday"
fmt.format(Direction.PLAIN, AbsoluteUnit.SUNDAY); // "Sunday"
fmt.format(Direction.LAST, AbsoluteUnit.DAY); // "yesterday"
fmt.format(Direction.THIS, AbsoluteUnit.DAY); // "today"
fmt.format(Direction.NEXT, AbsoluteUnit.DAY); // "tomorrow"
fmt.format(Direction.PLAIN, AbsoluteUnit.NOW); // "now"
- mavesonzini
1
1这是一个 Android 库，而不是一个 Java 库。 - Madbreaks
0
这是我的Java实现
public static String relativeDate(Date date){
Date now=new Date();
if(date.before(now)){
int days_passed=(int) TimeUnit.MILLISECONDS.toDays(now.getTime() - date.getTime());
if(days_passed>1)return days_passed+" days ago";
else{
int hours_passed=(int) TimeUnit.MILLISECONDS.toHours(now.getTime() - date.getTime());
if(hours_passed>1)return days_passed+" hours ago";
else{
int minutes_passed=(int) TimeUnit.MILLISECONDS.toMinutes(now.getTime() - date.getTime());
if(minutes_passed>1)return minutes_passed+" minutes ago";
else{
int seconds_passed=(int) TimeUnit.MILLISECONDS.toSeconds(now.getTime() - date.getTime());
return seconds_passed +" seconds ago";
}
}
}
}
else
{
return new SimpleDateFormat("HH:mm:ss MM/dd/yyyy").format(date).toString();
}
}
- Joey Pinto
0
关于这个问题，我已经完成了刚刚、几秒前、几分钟前、几小时前、几天前、几周前、几个月前、几年前等功能。在此示例中，您可以解析日期，例如2018-09-05T06:40:46.183Z或下面的任何其他日期格式。
请在string.xml中添加以下值。
<string name="lbl_justnow">Just Now</string>
<string name="lbl_seconds_ago">seconds ago</string>
<string name="lbl_min_ago">min ago</string>
<string name="lbl_mins_ago">mins ago</string>
<string name="lbl_hr_ago">hr ago</string>
<string name="lbl_hrs_ago">hrs ago</string>
<string name="lbl_day_ago">day ago</string>
<string name="lbl_days_ago">days ago</string>
<string name="lbl_lstweek_ago">last week</string>
<string name="lbl_week_ago">weeks ago</string>
<string name="lbl_onemonth_ago">1 month ago</string>
<string name="lbl_month_ago">months ago</string>
<string name="lbl_oneyear_ago" >last year</string>
<string name="lbl_year_ago" >years ago</string>
尝试下面的 Java 代码
public String getFormatDate(String postTime1) {
Calendar cal=Calendar.getInstance();
Date now=cal.getTime();
String disTime="";
try {
Date postTime;
//2018-09-05T06:40:46.183Z
postTime = new SimpleDateFormat("yyyy-MM-dd'T'HH:mm:ss.SSS'Z'").parse(postTime1);
long diff=(now.getTime()-postTime.getTime()+18000)/1000;
//for months
Calendar calObj = Calendar.getInstance();
calObj.setTime(postTime);
int m=calObj.get(Calendar.MONTH);
calObj.setTime(now);
SimpleDateFormat monthFormatter = new SimpleDateFormat("MM"); // output month
int mNow = Integer.parseInt(monthFormatter.format(postTime));
diff = diff-19800;
if(diff<15) { //below 15 sec
disTime = getResources().getString(R.string.lbl_justnow);
} else if(diff<60) {
//below 1 min
disTime= diff+" "+getResources().getString(R.string.lbl_seconds_ago);
} else if(diff<3600) {//below 1 hr
// convert min
long temp=diff/60;
if(temp==1) {
disTime= temp + " " +getResources().getString(R.string.lbl_min_ago);
} else {
disTime = temp + " " +getResources().getString(R.string.lbl_mins_ago);
}
} else if(diff<(24*3600)) {// below 1 day
// convert hr
long temp= diff/3600;
System.out.println("hey temp3:"+temp);
if(temp==1) {
disTime = temp + " " +getResources().getString(R.string.lbl_hr_ago);
} else {
disTime = temp + " " +getResources().getString(R.string.lbl_hrs_ago);
}
} else if(diff<(24*3600*7)) {// below week
// convert days
long temp=diff/(3600*24);
if (temp==1) {
// disTime = "\nyesterday";
disTime = temp + " " +getResources().getString(R.string.lbl_day_ago);
} else {
disTime = temp + " " +getResources().getString(R.string.lbl_days_ago);
}
} else if(diff<((24*3600*28))) {// below month
// convert week
long temp=diff/(3600*24*7);
if (temp <= 4) {
if (temp < 1) {
disTime = getResources().getString(R.string.lbl_lstweek_ago);
}else{
disTime = temp + " " + getResources().getString(R.string.lbl_week_ago);
}
} else {
int diffMonth = mNow - m;
Log.e("count : ", String.valueOf(diffMonth));
disTime = diffMonth + " " + getResources().getString(R.string.lbl_month_ago);
}
}else if(diff<((24*3600*365))) {// below year
// convert month
long temp=diff/(3600*24*30);
System.out.println("hey temp2:"+temp);
if (temp <= 12) {
if (temp == 1) {
disTime = getResources().getString(R.string.lbl_onemonth_ago);
}else{
disTime = temp + " " + getResources().getString(R.string.lbl_month_ago);
}
}
}else if(diff>((24*3600*365))) { // above year
// convert year
long temp=diff/(3600*24*30*12);
System.out.println("hey temp8:"+temp);
if (temp == 1) {
disTime = getResources().getString(R.string.lbl_oneyear_ago);
}else{
disTime = temp + " " + getResources().getString(R.string.lbl_year_ago);
}
}
} catch(Exception e) {
e.printStackTrace();
}
return disTime;
}
- Omkar
1
如果您正在开发Android应用程序，可以使用以下代码：android.text.format.DateUtils.getRelativeTimeSpanString(milliseconds) - Wajid
0
这是非常基础的脚本。很容易改进。
结果：（XXX小时前），或（XX天前/昨天/今天）
<span id='hourpost'></span>
,or
<span id='daypost'></span>
<script>
var postTime = new Date('2017/6/9 00:01');
var now = new Date();
var difference = now.getTime() - postTime.getTime();
var minutes = Math.round(difference/60000);
var hours = Math.round(minutes/60);
var days = Math.round(hours/24);
var result;
if (days < 1) {
result = "Today";
} else if (days < 2) {
result = "Yesterday";
} else {
result = days + " Days ago";
}
document.getElementById("hourpost").innerHTML = hours + "Hours Ago" ;
document.getElementById("daypost").innerHTML = result ;
</script>
- Dwipa Arantha
0
我正在使用Instant、Date和DateTimeUtils。数据（日期）以String类型存储在数据库中，然后转换为Instant。
/*
This method is to display ago.
Example: 3 minutes ago.
I already implement the latest which is including the Instant.
Convert from String to Instant and then parse to Date.
*/
public String convertTimeToAgo(String dataDate) {
//Initialize
String conversionTime = null;
String suffix = "Yang Lalu";
Date pastTime;
//Parse from String (which is stored as Instant.now().toString()
//And then convert to become Date
Instant instant = Instant.parse(dataDate);
pastTime = DateTimeUtils.toDate(instant);
//Today date
Date nowTime = new Date();
long dateDiff = nowTime.getTime() - pastTime.getTime();
long second = TimeUnit.MILLISECONDS.toSeconds(dateDiff);
long minute = TimeUnit.MILLISECONDS.toMinutes(dateDiff);
long hour = TimeUnit.MILLISECONDS.toHours(dateDiff);
long day = TimeUnit.MILLISECONDS.toDays(dateDiff);
if (second < 60) {
conversionTime = second + " Saat " + suffix;
} else if (minute < 60) {
conversionTime = minute + " Minit " + suffix;
} else if (hour < 24) {
conversionTime = hour + " Jam " + suffix;
} else if (day >= 7) {
if (day > 30) {
conversionTime = (day / 30) + " Bulan " + suffix;
} else if (day > 360) {
conversionTime = (day / 360) + " Tahun " + suffix;
} else {
conversionTime = (day / 7) + " Minggu " + suffix;
}
} else if (day < 7) {
conversionTime = day + " Hari " + suffix;
}
return conversionTime;
}
- Ticherhaz FreePalestine
3
1你正在使用过时的日期时间类，这些类已经在多年前被 java.time 类所取代。 - Basil Bourque
@BasilBourque 我仍然找不到最新的方法来做这件事。 - Ticherhaz FreePalestine
@BasilBourque 我添加了一些代码以便我理解它。https://github.com/ticherhaz/tarikhmasa - Ticherhaz FreePalestine
0
这是我的测试用例，希望能有所帮助：
val currentCalendar = Calendar.getInstance()
currentCalendar.set(2019, 6, 2, 5, 31, 0)
val targetCalendar = Calendar.getInstance()
targetCalendar.set(2019, 6, 2, 5, 30, 0)
val diffTs = currentCalendar.timeInMillis - targetCalendar.timeInMillis
val diffMins = TimeUnit.MILLISECONDS.toMinutes(diffTs)
val diffHours = TimeUnit.MILLISECONDS.toHours(diffTs)
val diffDays = TimeUnit.MILLISECONDS.toDays(diffTs)
val diffWeeks = TimeUnit.MILLISECONDS.toDays(diffTs) / 7
val diffMonths = TimeUnit.MILLISECONDS.toDays(diffTs) / 30
val diffYears = TimeUnit.MILLISECONDS.toDays(diffTs) / 365
val newTs = when {
diffYears >= 1 -> "Years $diffYears"
diffMonths >= 1 -> "Months $diffMonths"
diffWeeks >= 1 -> "Weeks $diffWeeks"
diffDays >= 1 -> "Days $diffDays"
diffHours >= 1 -> "Hours $diffHours"
diffMins >= 1 -> "Mins $diffMins"
else -> "now"
}
- David_Wang
2
1可怕的
Calendar类在多年前已被现代java.time类所取代，而这是在采用了[JSR 310]（https://jcp.org/en/jsr/detail?id=310）之后。这是2019年的不良建议。 - Basil Bourque你可能是想用
var 而不是 val。 - Basil Bourque0
以下解决方案均为纯Java：
选项1：不进行四舍五入，仅显示最大时间容器
以下函数仅会显示最大的时间容器，例如，如果真实经过的时间是"1个月14天前"，该函数将只显示"1个月前"。此函数始终向下取整，因此等同于"50天前"的时间将显示为"1个月"
public String formatTimeAgo(long millis) {
String[] ids = new String[]{"second","minute","hour","day","month","year"};
long seconds = millis / 1000;
long minutes = seconds / 60;
long hours = minutes / 60;
long days = hours / 24;
long months = days / 30;
long years = months / 12;
ArrayList<Long> times = new ArrayList<>(Arrays.asList(years, months, days, hours, minutes, seconds));
for(int i = 0; i < times.size(); i++) {
if(times.get(i) != 0) {
long value = times.get(i).intValue();
return value + " " + ids[ids.length - 1 - i] + (value == 1 ? "" : "s") + " ago";
}
}
return "0 seconds ago";
}
选项2：四舍五入
只需使用Math.round（...）语句包装您想要四舍五入的时间容器，因此如果您想将 50天四舍五入为 2个月，请修改 long months = days / 30 到 long months = Math.round（days / 30.0）
- widavies
1
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