我正在给我的安卓应用添加通知功能,但是似乎无法通过我的Java代码发送通知。我从响应中获得了200 Http状态码,但是没有任何内容显示。
这在Firebase控制台本身上运行良好,但是一旦我尝试使用我的Java代码,问题就出现了。
以下是我的代码:
package actions.authentication;
import java.io.BufferedReader;
import java.io.InputStreamReader;
import java.io.OutputStreamWriter;
import java.net.HttpURLConnection;
import java.net.URL;
import com.opensymphony.xwork2.Action;
import edocs.actions.PublicAction;
import net.sf.json.JSONObject;
public class SendPushNotification extends PublicAction {
/**
*
*/
private static final long serialVersionUID = -8022560668279505764L;
// Method to send Notifications from server to client end.
public final static String AUTH_KEY_FCM = "SERVER_KEY_HERE";
public final static String API_URL_FCM = "https://fcm.googleapis.com/fcm/send";
public final static String DEVICE_ID = "DEVICE_TOKEN_HERE";
public String execute() {
String DeviceIdKey = DEVICE_ID;
String authKey = AUTH_KEY_FCM;
String FMCurl = API_URL_FCM;
try {
URL url = new URL(FMCurl);
HttpURLConnection conn = (HttpURLConnection) url.openConnection();
conn.setUseCaches(false);
conn.setDoInput(true);
conn.setDoOutput(true);
conn.setRequestMethod("POST");
conn.setRequestProperty("Authorization", "key=" + authKey);
conn.setRequestProperty("Content-Type", "application/json");
System.out.println(DeviceIdKey);
JSONObject data = new JSONObject();
data.put("to", DeviceIdKey.trim());
JSONObject info = new JSONObject();
info.put("title", "FCM Notificatoin Title"); // Notification title
info.put("body", "Hello First Test notification"); // Notification body
data.put("data", info);
System.out.println(data.toString());
OutputStreamWriter wr = new OutputStreamWriter(conn.getOutputStream());
wr.write(data.toString());
wr.flush();
wr.close();
int responseCode = conn.getResponseCode();
System.out.println("Response Code : " + responseCode);
BufferedReader in = new BufferedReader(new InputStreamReader(conn.getInputStream()));
String inputLine;
StringBuffer response = new StringBuffer();
while ((inputLine = in.readLine()) != null) {
response.append(inputLine);
}
in.close();
return Action.SUCCESS;
}
catch(Exception e)
{
System.out.println(e);
}
return Action.SUCCESS;
}
}
这行代码 System.out.println("Response Code : " + responseCode);
输出以下内容
响应码 : 200
有其他人遇到过这个问题吗?非常感谢您的帮助。