我有一个使用 numpy.longdouble
类型的时间,当我试图将这些值与 timedelta
函数一起使用时,会出现错误。但是,当我将其转换为 numpy.float64
类型时,一切都正常。有人可以解释一下这种行为吗?
import numpy as np
from datetime import timedelta
t1 = np.array([1000], dtype=np.longdouble)
t2 = np.array([1000], dtype=np.float64)
In [166]: timedelta(seconds=t1[0])
TypeError: unsupported type for timedelta seconds component: numpy.float64
In [167]: timedelta(seconds=t2[0])
Out[167]: datetime.timedelta(0, 1000)
In [168]: timedelta(seconds=t1[0].astype(np.float64))
Out[168]: datetime.timedelta(0, 1000)
当我试图查看变量的数据类型时,它们看起来类似但并不相同:
In [172]: t1[0].dtype
Out[172]: dtype('float64')
In [173]: t2[0].dtype
Out[173]: dtype('float64')
In [174]: np.longdouble == np.float64
Out[174]: False
In [175]: t1[0].dtype == t2[0].dtype
Out[175]: True
编辑
而且奇怪的是,它对于np.int32和np.int64也不起作用:
t3 = np.array([1000], dtype=np.int32)
t4 = np.array([1000], dtype=np.int64)
In [29]: timedelta(t3[0])
TypeError: unsupported type for timedelta days component: numpy.int32
In [69]: timedelta(t4[0])
TypeError: unsupported type for timedelta days component: numpy.int64