我可以为您提供以下结果：$name = 'Doron'; $email = 'doron@myemail.com'; $phone = '0501234567';。

Question

我可以为您提供以下结果：$name = 'Doron'; $email = 'doron@myemail.com'; $phone = '0501234567';。

4

我想从我的JSON中提取以下数据：

$name = 'Doron';
$email = 'doron@myemail.com';
$phone = '0501234567';

这是一个多维数组。电子邮件有一个键 type:email，电话有 type:tel，姓名有 id:name

$myJson = '[
{
"name":
{"id":"name","type":"text","title":"","value":"Doron","raw_value":"Doron", "required":"0"}
,
"email":
{"id":"email","type":"email","title":"","value":"doron@myemail.com", "raw_value":"doron@myemail.com","required":"1"},
"4729ed5":
{"id":"4729ed5","type":"tel","title":"","value":"0501234567", "raw_value":"0501234567","required":"0"}
}]';

// Convert JSON string to Array
$FieldsArray = json_decode($myJson, true);

- salman ifrahim

1个回答

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- Shashin Bhayani · Accepted Answer

最初的回答：您可以像这样访问这些值：

您可以通过以下方式访问这些值

$myJson = '[
{
"name":
{"id":"name","type":"text","title":"","value":"Doron","raw_value":"Doron", "required":"0"}
,
"email":
{"id":"email","type":"email","title":"","value":"doron@myemail.com", "raw_value":"doron@myemail.com","required":"1"},
"4729ed5":
{"id":"4729ed5","type":"tel","title":"","value":"0501234567", "raw_value":"0501234567","required":"0"}
}]';

// Convert JSON string to Array
$FieldsArray = json_decode($myJson, true);

$name = '';
$email = '';
$phone = '';

foreach ($FieldsArray[0] as $key=>$field) {

    if($field['id'] == 'name') {
        $name = $field['value'];
    } elseif($field['type'] == 'email') {
        $email = $field['value'];
    } elseif($field['type'] == 'tel') {
        $phone = $field['value'];
    }
}