我也用numpy发布了我的二分查找解决方案
class Stock():
def __init__(self, name, date):
self.name = name
self.date = np.array(date)
def __getitem__(self, key):
if isinstance(key, slice):
if key.start is not None and key.stop is not None:
return self.date[np.searchsorted(self.date, key.start, side='left', sorter=None):np.searchsorted(self.date, key.stop, side='left', sorter=None)]
elif key.start is not None:
return self.date[np.searchsorted(self.date, key.start, side='left', sorter=None):]
elif key.stop is not None:
return self.date[:np.searchsorted(self.date, key.stop, side='left', sorter=None)]
else:
return self.date[:]
i = np.searchsorted(self.date, key, side='left', sorter=None)
if key != self.date[i]:
raise KeyError('key: {} was not found!'.format(key))
else:
return self.date[i]
aapl = Stock('aapl', ['2010','2012', '2014', '2016', '2018'])
print(aapl['2011':])
print(aapl['2014':'2017'])
print(aapl[:'2016'])
print(aapl['2010'])
print(aapl['2013'])
'''
['2012' '2014' '2016' '2018']
['2014' '2016']
['2010' '2012' '2014']
2010
Traceback (most recent call last):
File "C:\Users\...\Desktop\...\stock.py", line ##, in <module>
print(aapl['2013'])
File "C:\Users\...\Desktop\...\stock.py", line ##, in __getitem__
raise KeyError('key: {} was not found!'.format(key))
KeyError: 'key: 2013 was not found!'
'''
arr['B':'M']
会提供你提供的输出。也许你的意思是arr['B':'N']
?另外,如果有多个字符串以相同的字母开头,会发生什么? - DeepSpacebisect
库。 - Chris_Rands