我目前正在使用一台配备了4张 Tesla T10 GPU 的GPU服务器。在测试内核时,我经常需要使用 ctrl-C 来终止进程,因此我在一个简单的设备查询代码末尾添加了几行代码。以下是代码:
#include <stdio.h>
// Print device properties
void printDevProp(cudaDeviceProp devProp)
{
printf("Major revision number: %d\n", devProp.major);
printf("Minor revision number: %d\n", devProp.minor);
printf("Name: %s\n", devProp.name);
printf("Total global memory: %u\n", devProp.totalGlobalMem);
printf("Total shared memory per block: %u\n", devProp.sharedMemPerBlock);
printf("Total registers per block: %d\n", devProp.regsPerBlock);
printf("Warp size: %d\n", devProp.warpSize);
printf("Maximum memory pitch: %u\n", devProp.memPitch);
printf("Maximum threads per block: %d\n", devProp.maxThreadsPerBlock);
for (int i = 0; i < 3; ++i)
printf("Maximum dimension %d of block: %d\n", i, devProp.maxThreadsDim[i]);
for (int i = 0; i < 3; ++i)
printf("Maximum dimension %d of grid: %d\n", i, devProp.maxGridSize[i]);
printf("Clock rate: %d\n", devProp.clockRate);
printf("Total constant memory: %u\n", devProp.totalConstMem);
printf("Texture alignment: %u\n", devProp.textureAlignment);
printf("Concurrent copy and execution: %s\n", (devProp.deviceOverlap ? "Yes" : "No"));
printf("Number of multiprocessors: %d\n", devProp.multiProcessorCount);
printf("Kernel execution timeout: %s\n", (devProp.kernelExecTimeoutEnabled ? "Yes" : "No"));
return;
}
int main()
{
// Number of CUDA devices
int devCount;
cudaGetDeviceCount(&devCount);
printf("CUDA Device Query...\n");
printf("There are %d CUDA devices.\n", devCount);
// Iterate through devices
for (int i = 0; i < devCount; ++i)
{
// Get device properties
printf("\nCUDA Device #%d\n", i);
cudaDeviceProp devProp;
cudaGetDeviceProperties(&devProp, i);
printDevProp(devProp);
}
printf("\nPress any key to exit...");
char c;
scanf("%c", &c);
**for (int i = 0; i < devCount; i++) {
cudaSetDevice(i);
cudaDeviceReset();
}**
return 0;
}
我的问题与主函数结束前的for循环有关,我在其中逐个设置每个设备,然后使用cudaResetDevice命令。虽然这段代码没有产生任何错误,但我感到奇怪的是我无法重置所有设备。相反,程序每次只重置默认设备即设备0。有人能告诉我应该怎么做才能重置4个设备中的每一个吗?
谢谢。