我认为在MFC视图上显示OpenCV2 Mat看似简单,但实际上却不然。我在谷歌上找到的唯一相关材料是这个:This is only relevant material I found on google。抱歉我的无知,但我找不到其他任何资料展示如何使用带有单维数组"data"成员返回的SetDIBitsToDevice函数。更具体地说,我需要知道如何为该函数指定BITMAPINFO。我要回到旧的C风格的OpenCV来处理MFC么?
更新:
我找到了一个SetDIBitsToDevice的例子,它实际上是针对旧的C风格OpenCV的。但将其转换为OpenCV2很简单。有几件事情需要注意才能使其工作:
更新:
我找到了一个SetDIBitsToDevice的例子,它实际上是针对旧的C风格OpenCV的。但将其转换为OpenCV2很简单。有几件事情需要注意才能使其工作:
Bpp method does not work well as Mat's depth returns 0. I just changed like this:
static int Bpp(cv::Mat img) { return 8 * img.channels(); }
Mat does not have origin member. But simply putting 0 is fine for origin argument of FillBitmapInfo method.
void COpenCVTestView::OnDraw(CDC* pDC)
{
COpenCVTestDoc* pDoc = GetDocument();
ASSERT_VALID(pDoc);
if (!pDoc)
return;
if(pDoc->m_cvImage.empty()) return;
// TODO: add draw code for native data here
int height=pDoc->m_cvImage.rows;
int width=pDoc->m_cvImage.cols;
uchar buffer[sizeof( BITMAPINFOHEADER ) + 1024];
BITMAPINFO* bmi = (BITMAPINFO* )buffer;
FillBitmapInfo(bmi,width,height,Bpp(pDoc->m_cvImage),0);
SetDIBitsToDevice(pDC->GetSafeHdc(), 0, 0, width,
height, 0, 0, 0, height, pDoc->m_cvImage.data, bmi,
DIB_RGB_COLORS);
}
void COpenCVTestView::FillBitmapInfo(BITMAPINFO* bmi, int width, int height, int bpp, int origin)
{
assert(bmi && width >= 0 && height >= 0 && (bpp == 8 || bpp == 24 || bpp == 32));
BITMAPINFOHEADER* bmih = &(bmi->bmiHeader);
memset(bmih, 0, sizeof(*bmih));
bmih->biSize = sizeof(BITMAPINFOHEADER);
bmih->biWidth = width;
bmih->biHeight = origin ? abs(height) : -abs(height);
bmih->biPlanes = 1;
bmih->biBitCount = (unsigned short)bpp;
bmih->biCompression = BI_RGB;
if (bpp == 8)
{
RGBQUAD* palette = bmi->bmiColors;
for (int i = 0; i < 256; i++)
{
palette[i].rgbBlue = palette[i].rgbGreen = palette[i].rgbRed = (BYTE)i;
palette[i].rgbReserved = 0;
}
}
}
FillBitmapInfo
函数中使用memset
时,你是如何避免内存泄漏的?或者说它会自动释放吗?你能详细说明一下吗? - adnSetDIBitsToDevice
调用,但BITMAPINFO
对于初学者来说可能会有些困惑。 - Raymond