我想把两个列表中的列表项分开。
a = [[1, 0, 2], [0, 0, 0], [1], [1]]
b = [[5, 6, 4], [6, 6, 6], [3], [3]]
我该如何将 a 除以 b 并得到以下输出结果:
c = [[0.2, 0, 0.5], [0, 0, 0], [0.333], [0.333]]
有人能帮我吗?
将两个列表压缩,使用列表推导式:
from __future__ import division # in python2 only
result = [[x/y for x,y in zip(xs, ys)] for xs, ys in zip(a, b)]
示例运行:
In [1]: a = [[1, 0, 2], [0, 0, 0], [1], [1]]
...: b = [[5, 6, 4], [6, 6, 6], [3], [3]]
...:
In [2]: result = [[x/y for x,y in zip(xs, ys)] for xs, ys in zip(a, b)]
In [3]: result
Out[3]: [[0.2, 0.0, 0.5], [0.0, 0.0, 0.0], [0.3333333333333333], [0.3333333333333333]]
使用 itertools.izip
(Python 2.7):
import itertools
[[float(aaa) / bbb for (aaa, bbb) in itertools.izip(aa, bb)] \
for (aa, bb) in itertools.izip(a, b)]
from __future__ import division # for Python2
[[x / y for x, y in zip(*item)] for item in zip(a, b)]
[[0, 0, 0], [0, 0, 0], [0], [0]]
作为输出?(我使用的是Python 2.7) - Aviónfrom __future__ import division
。在Python2中,默认情况下/
运算符是整数除法,而实际上你需要浮点除法。 - Bakuriu