什么是使C++程序崩溃的最简单方法？

If the exception handling mechanism, after completing the initialization of the exception object but before the activation of a handler for the exception, calls a function that exits via an exception, std::terminate is called (15.5.1).

struct C {
    C() { }
    C(const C&) {
        if (std::uncaught_exceptions()) {
            throw 0; // throw during copy to handler’s exception-declaration object (15.3)
        }
    }
};
int main() {
    try {
    throw C(); // calls std::terminate() if construction of the handler’s
    // exception-declaration object is not elided (12.8)
    } catch(C) { }
}

我写了一个小代码来演示这个问题，可以在Ideone这里找到并尝试。

class MyClass{
    public:
    ~MyClass() throw(int) { throw 0;}
};

int main() {
  try {
    MyClass myobj; // its destructor will cause an exception

    // This is another exception along with exception due to destructor of myobj and will cause app to terminate
     throw 1;      // It could be some function call which can result in exception.
  }
  catch(...)
  {
    std::cout<<"Exception catched"<<endl;
  }
  return 0;
}

ISO/IEC 14882 §15.1/9提到，没有try块的throw会导致隐式调用abort：

如果当前没有正在处理的异常，并且执行一个没有操作数的throw表达式，则调用std::terminate()

其他情况包括： 从析构函数中抛出： ISO/IEC 14882 §15.2/3