在PHP中有这两个数组:
$array1 = [
2 => 'Search',
1 => 'Front-End / GUI'
];
$array2 = [
1 => 'Front-End / GUI',
2 => 'Search'
];
大多数数组比较函数对顺序不关心。使用
array_diff
会得到一个空数组。关于顺序,比较两个数组最有效/最短/最简洁的方法是什么?
- 显示它们是否相等(true / false)?
- 显示区别(例如PHPUnit)?
$this->assertEquals($array1,$array2);
理想情况下应该产生类似以下结果:Failed asserting that two arrays are equal.
--- Expected
+++ Actual
@@ @@
Array (
- 2 => 'Search'
- 1 => 'Front-End / GUI'
+ 1 => 'Front-End / GUI'
+ 2 => 'Search'
)
更新 - 解决方案
只有在所有元素相同但顺序不同的情况下,这将生成一种类似的差异。PHPUnit测试:
public function test...() {
$actual = someCall();
$expected = [...];
// tests for same elements
$this->assertEquals( $expected, $actual );
// tests for same order
$diff = $this->array_diff_order( $expected, $actual );
$this->assertTrue( $expected === $actual, "Failed asserting that two arrays are equal order.\n--- Expected\n+++ Actual\n@@ @@\n Array(\n$diff )" );
}
private function array_diff_order( $array1, $array2 ) {
$out = '';
while ((list($key1, $val1) = each($array1)) && (list($key2, $val2) = each($array2)) ) {
if($key1 != $key2 || $val1 != $val2) $out .= "- $key1 => '$val1' \n+ $key2 => '$val2'\n";
}
return $out;
}
array_diff_assoc()
不会检查顺序。Marc 的第二个数组与我的不同。 - Joe Z