有没有人知道一种T-SQL脚本,可以检测整个数据库中的冗余索引?表中一个冗余索引的例子如下:
Index 1: 'ColumnA', 'ColumnB', 'ColumnC'
Index 2: 'ColumnA', 'ColumnB'
忽略其他考虑因素,比如列宽和覆盖索引,第二个索引是多余的。谢谢。
有没有人知道一种T-SQL脚本,可以检测整个数据库中的冗余索引?表中一个冗余索引的例子如下:
Index 1: 'ColumnA', 'ColumnB', 'ColumnC'
Index 2: 'ColumnA', 'ColumnB'
有些情况下冗余并不适用。例如,假设ColumnC
是一个非常大的字段,但有时需要快速检索它。在这种情况下,您的index 1
将不需要进行键查找:
select ColumnC from YourTable where ColumnnA = 12
另一方面,索引2
要小得多,因此可以在需要索引扫描的查询中在内存中读取:
select * from YourTable where ColumnnA like '%hello%'
所以它们并不是真正的冗余。
如果您不相信我上面的论点,您可以找到像“冗余”索引这样的内容:
;with ind as (
select a.object_id
, a.index_id
, cast(col_list.list as varchar(max)) as list
from (
select distinct object_id
, index_id
from sys.index_columns
) a
cross apply
(
select cast(column_id as varchar(16)) + ',' as [text()]
from sys.index_columns b
where a.object_id = b.object_id
and a.index_id = b.index_id
for xml path(''), type
) col_list (list)
)
select object_name(a.object_id) as TableName
, asi.name as FatherIndex
, bsi.name as RedundantIndex
from ind a
join sys.sysindexes asi
on asi.id = a.object_id
and asi.indid = a.index_id
join ind b
on a.object_id = b.object_id
and a.object_id = b.object_id
and len(a.list) > len(b.list)
and left(a.list, LEN(b.list)) = b.list
join sys.sysindexes bsi
on bsi.id = b.object_id
and bsi.indid = b.index_id
在性能“意外”下降的情况下,为你的用户带来蛋糕吧 :-)
在受Paul Nielsen启发的情况下,我编写了这个查询来查找/区分:
并记录它们的使用情况
(也许有人想使用is_descending_key
,但我不需要。)
WITH IndexColumns AS
(
SELECT I.object_id AS TableObjectId, OBJECT_SCHEMA_NAME(I.object_id) + '.' + OBJECT_NAME(I.object_id) AS TableName, I.index_id AS IndexId, I.name AS IndexName
, (IndexUsage.user_seeks + IndexUsage.user_scans + IndexUsage.user_lookups) AS IndexUsage
, IndexUsage.user_updates AS IndexUpdates
, (SELECT CASE is_included_column WHEN 1 THEN NULL ELSE column_id END AS [data()]
FROM sys.index_columns AS IndexColumns
WHERE IndexColumns.object_id = I.object_id
AND IndexColumns.index_id = I.index_id
ORDER BY index_column_id, column_id
FOR XML PATH('')
) AS ConcIndexColumnNrs
,(SELECT CASE is_included_column WHEN 1 THEN NULL ELSE COL_NAME(I.object_id, column_id) END AS [data()]
FROM sys.index_columns AS IndexColumns
WHERE IndexColumns.object_id = I.object_id
AND IndexColumns.index_id = I.index_id
ORDER BY index_column_id, column_id
FOR XML PATH('')
) AS ConcIndexColumnNames
,(SELECT CASE is_included_column WHEN 1 THEN column_id ELSE NULL END AS [data()]
FROM sys.index_columns AS IndexColumns
WHERE IndexColumns.object_id = I.object_id
AND IndexColumns.index_id = I.index_id
ORDER BY column_id
FOR XML PATH('')
) AS ConcIncludeColumnNrs
,(SELECT CASE is_included_column WHEN 1 THEN COL_NAME(I.object_id, column_id) ELSE NULL END AS [data()]
FROM sys.index_columns AS IndexColumns
WHERE IndexColumns.object_id = I.object_id
AND IndexColumns.index_id = I.index_id
ORDER BY column_id
FOR XML PATH('')
) AS ConcIncludeColumnNames
FROM sys.indexes AS I
LEFT OUTER JOIN sys.dm_db_index_usage_stats AS IndexUsage
ON IndexUsage.object_id = I.object_id
AND IndexUsage.index_id = I.index_id
AND IndexUsage.Database_id = db_id()
)
SELECT
C1.TableName
, C1.IndexName AS 'Index1'
, C2.IndexName AS 'Index2'
, CASE WHEN (C1.ConcIndexColumnNrs = C2.ConcIndexColumnNrs) AND (C1.ConcIncludeColumnNrs = C2.ConcIncludeColumnNrs) THEN 'Exact duplicate'
WHEN (C1.ConcIndexColumnNrs = C2.ConcIndexColumnNrs) THEN 'Different includes'
ELSE 'Overlapping columns' END
-- , C1.ConcIndexColumnNrs
-- , C2.ConcIndexColumnNrs
, C1.ConcIndexColumnNames
, C2.ConcIndexColumnNames
-- , C1.ConcIncludeColumnNrs
-- , C2.ConcIncludeColumnNrs
, C1.ConcIncludeColumnNames
, C2.ConcIncludeColumnNames
, C1.IndexUsage
, C2.IndexUsage
, C1.IndexUpdates
, C2.IndexUpdates
, 'DROP INDEX ' + C2.IndexName + ' ON ' + C2.TableName AS Drop2
, 'DROP INDEX ' + C1.IndexName + ' ON ' + C1.TableName AS Drop1
FROM IndexColumns AS C1
INNER JOIN IndexColumns AS C2
ON (C1.TableObjectId = C2.TableObjectId)
AND (
-- exact: show lower IndexId as 1
(C1.IndexId < C2.IndexId
AND C1.ConcIndexColumnNrs = C2.ConcIndexColumnNrs
AND C1.ConcIncludeColumnNrs = C2.ConcIncludeColumnNrs)
-- different includes: show longer include as 1
OR (C1.ConcIndexColumnNrs = C2.ConcIndexColumnNrs
AND LEN(C1.ConcIncludeColumnNrs) > LEN(C2.ConcIncludeColumnNrs))
-- overlapping: show longer index as 1
OR (C1.IndexId <> C2.IndexId
AND C1.ConcIndexColumnNrs <> C2.ConcIndexColumnNrs
AND C1.ConcIndexColumnNrs like C2.ConcIndexColumnNrs + ' %')
)
ORDER BY C1.TableName, C1.ConcIndexColumnNrs
尝试使用下面的脚本来显示未使用的索引,希望能够帮助。
/****************************************************************
Description: Script to show Unused Indexes using DMVs
****************************************************************/
SELECT TOP 100
o.name AS ObjectName
, i.name AS IndexName
, i.index_id AS IndexID
, dm_ius.user_seeks AS UserSeek
, dm_ius.user_scans AS UserScans
, dm_ius.user_lookups AS UserLookups
, dm_ius.user_updates AS UserUpdates
, p.TableRows
, 'DROP INDEX ' + QUOTENAME(i.name)
+ ' ON ' + QUOTENAME(s.name) + '.' + QUOTENAME(OBJECT_NAME(dm_ius.object_id)) as 'drop statement'
FROM sys.dm_db_index_usage_stats dm_ius
INNER JOIN sys.indexes i ON i.index_id = dm_ius.index_id AND dm_ius.object_id = i.object_id
INNER JOIN sys.objects o on dm_ius.object_id = o.object_id
INNER JOIN sys.schemas s on o.schema_id = s.schema_id
INNER JOIN (SELECT SUM(p.rows) TableRows, p.index_id, p.object_id
FROM sys.partitions p GROUP BY p.index_id, p.object_id) p
ON p.index_id = dm_ius.index_id AND dm_ius.object_id = p.object_id
WHERE OBJECTPROPERTY(dm_ius.object_id,'IsUserTable') = 1
AND dm_ius.database_id = DB_ID()
AND i.type_desc = 'nonclustered'
AND i.is_primary_key = 0
AND i.is_unique_constraint = 0
ORDER BY (dm_ius.user_seeks + dm_ius.user_scans + dm_ius.user_lookups) ASC
GO
我创建了以下查询,给出了很多有用的信息来识别重复和接近重复的索引。还包括其他信息,如索引占用的内存页数,这使我能够优先考虑较大的索引。它显示哪些列已经建立了索引,哪些列已经被包含在内,因此我可以看到是否存在两个几乎相同的索引,只有包含列略有不同。
WITH IndexSummary AS
(
SELECT DISTINCT sys.objects.name AS [Table Name],
sys.indexes.name AS [Index Name],
SUBSTRING((SELECT ', ' + sys.columns.Name as [text()]
FROM sys.columns
INNER JOIN sys.index_columns
ON sys.index_columns.column_id = sys.columns.column_id
AND sys.index_columns.object_id = sys.columns.object_id
WHERE sys.index_columns.index_id = sys.indexes.index_id
AND sys.index_columns.object_id = sys.indexes.object_id
AND sys.index_columns.is_included_column = 0
ORDER BY sys.columns.name
FOR XML Path('')), 2, 10000) AS [Indexed Column Names],
ISNULL(SUBSTRING((SELECT ', ' + sys.columns.Name as [text()]
FROM sys.columns
INNER JOIN sys.index_columns
ON sys.index_columns.column_id = sys.columns.column_id
AND sys.index_columns.object_id = sys.columns.object_id
WHERE sys.index_columns.index_id = sys.indexes.index_id
AND sys.index_columns.object_id = sys.indexes.object_id
AND sys.index_columns.is_included_column = 1
ORDER BY sys.columns.name
FOR XML Path('')), 2, 10000), '') AS [Included Column Names],
sys.indexes.index_id, sys.indexes.object_id
FROM sys.indexes
INNER JOIN SYS.index_columns
ON sys.indexes.index_id = SYS.index_columns.index_id
AND sys.indexes.object_id = sys.index_columns.object_id
INNER JOIN sys.objects
ON sys.OBJECTS.object_id = SYS.indexES.object_id
WHERE sys.objects.type = 'U'
)
SELECT IndexSummary.[Table Name],
IndexSummary.[Index Name],
IndexSummary.[Indexed Column Names],
IndexSummary.[Included Column Names],
PhysicalStats.page_count as [Page Count],
CONVERT(decimal(18,2), PhysicalStats.page_count * 8 / 1024.0) AS [Size (MB)],
CONVERT(decimal(18,2), PhysicalStats.avg_fragmentation_in_percent) AS [Fragment %]
FROM IndexSummary
INNER JOIN sys.dm_db_index_physical_stats (DB_ID(), NULL, NULL, NULL, NULL)
AS PhysicalStats
ON PhysicalStats.index_id = IndexSummary.index_id
AND PhysicalStats.object_id = IndexSummary.object_id
WHERE (SELECT COUNT(*) as Computed
FROM IndexSummary Summary2
WHERE Summary2.[Table Name] = IndexSummary.[Table Name]
AND Summary2.[Indexed Column Names] = IndexSummary.[Indexed Column Names]) > 1
ORDER BY [Table Name], [Index Name], [Indexed Column Names], [Included Column Names]
Results of the query look like this:
Table Name Index Indexed Cols Included Cols Pages Size (MB) Frag %
My_Table Indx_1 Col1 Col2, Col3 123 0.96 8.94
My_Table Indx_2 Col1 Col2, Col3 123 0.96 8.94
完整解释请参见在SQL Server中识别重复或冗余索引。